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(a) If \(\operatorname{dim}(V)=n,\) then there exists a set of \(n-1\) vectors in \(V\) that will span \(V\) (b) If \(\operatorname{dim}(V)=n,\) then there exists a set of \(n+1\) vectors in \(V\) that will span \(V\)

Short Answer

Expert verified
For part (a), no a set of \(n-1\) vectors cannot span \(V\). For part (b), yes a set of \(n+1\) vectors can span \(V\), but it will not form a basis of \(V\).

Step by step solution

01

Solution to part (a)

The dimension of a vector space is defined as the number of vectors in its basis. A basis of a vector space \(V\) is a set of vectors that are linearly independent and span \(V\). Hence, if \(\operatorname{dim}(V)=n\), it implies that a minimum of \(n\) vectors are necessary to span \(V\). Thus, it is not possible for a set of \(n-1\) vectors to span \(V\).
02

Solution to part (b)

If \(\operatorname{dim}(V)=n\), it means that we can have a set of \(n\) vectors that are linearly independent and can span \(V\). However, a set of \(n+1\) vectors in \(V\) would mean that at least one vector in the set is a linear combination of the other vectors, considering \(V\) is of dimension \(n\). Therefore, the additional vector does not contribute anything new to the span, meaning that a set of \(n+1\) vectors will also still span \(V\), though it will not be a basis due to the presence of linearly dependent vectors.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Basis of Vector Space
Understanding the basis of a vector space is essential for grasping the structure of the space itself. In simple terms, a basis is a set of vectors that are powerful enough to represent every single vector in the space through a process known as linear combination. Think of it as a set of essential building blocks from which everything in the space can be constructed.

A vector space's dimension, denoted as \( \operatorname{dim}(V) \), is the number of vectors in a basis for \( V \). Importantly, for the vector space to have a dimension of \( n \), it requires exactly \( n \), no more and no less, linearly independent vectors in its basis. Consequently, \( n-1 \) vectors would be inadequate—they simply don't have the 'muscle' to convey all information about vectors in the space. Each vector in a basis adds a new dimension, a new direction, not previously covered by the others.
Linearly Independent Vectors
Linear independence is a term that often intimidates students, but it need not be so. At its core, it speaks to uniqueness among vectors. A set of vectors is linearly independent if no vector in the set can be written as a combination of the others. It's like having a team where each member brings something unique to the table—no one's contribution can be duplicated by the others.

In a practical sense, when dealing with \( n \) linearly independent vectors in an \( n \) dimensional vector space, you’ve found a sturdy basis. This means that no matter which vector you choose in the space, it can be expressed uniquely using these \( n \) vectors. But, as soon as you have an additional vector, say \( n+1 \), linear independence is lost. There's bound to be some redundancy, as at least one vector can be recreated using a mix of the others. Still, even with this surplus vector, the collective set can span the vector space, though redundancy means the set is no longer a minimal basis.
Vector Span
Speaking of span, let’s unfurl this concept. The span of a set of vectors is the collection of all possible vectors that can be formed using linear combinations of the set. If you imagine a vector space as an infinite expanse of potential, think of the span as marking out a specific landscape within that vast territory.

Therefore, when we discuss a set of vectors spanning a vector space \( V \), we're saying they lay down the canvas for everything \( V \) encompasses. If a space is \( n \) dimensional, \( n \) well-chosen vectors can provide a span that covers the whole space. Add another vector to make it \( n+1 \) and you’re not expanding the span—you’re just adding another point that was already covered by the original \( n \) vectors. It's like adding another thread to an already complete tapestry; the picture doesn't change, but the thread still lingers.

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