Chapter 3: Problem 49
Determine whether the points are collinear. $$(1,2),(3,4),(5,6)$$
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Chapter 3: Problem 49
Determine whether the points are collinear. $$(1,2),(3,4),(5,6)$$
These are the key concepts you need to understand to accurately answer the question.
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Find the area of the triangle having the given vertices. $$(0,0),(2,0),(0,3)$$
Use Cramer's Rule to solve the system of linear equations, if possible. $$\begin{array}{l} 3 x_{1}+2 x_{2}=1 \\ 2 x_{1}+10 x_{2}=6 \end{array}$$
The table below shows the projected values (in millions of dollars) of hardback college textbooks sold in the United States for the years 2007 to \(2009 .\) (Source: U.S. Census Bureau) $$\begin{array}{l|c} \hline \text {Year} & \text {Value} \\ \hline 2007 & 4380 \\ 2008 & 4439 \\ 2009 & 4524 \\ \hline \end{array}$$ (a) Create a system of linear equations for the data to fit the curve \(y=a t^{2}+b t+c,\) where \(t\) is the year and \(t=7\) corresponds to \(2007,\) and \(y\) is the value of the textbooks. (b) Use Cramer's Rule to solve your system. (c) Use a graphing utility to plot the data and graph your regression polynomial function. (d) Briefly describe how well the polynomial function fits the data.
Verify that \(\lambda_{i}\) is an eigenvalue of \(A\) and that \(\mathbf{x}_{i}\) is a corresponding eigenvector. $$\begin{array}{l} A=\left[\begin{array}{rrr} 1 & -2 & 1 \\ 0 & 1 & 4 \\ 0 & 0 & 2 \end{array}\right] ; \quad \lambda_{1}=1, \quad \mathbf{x}_{1}=\left[\begin{array}{l} 1 \\ 0 \\ 0 \end{array}\right] \\ \lambda_{2}=2, \quad \mathbf{x}_{2}=\left[\begin{array}{r} -7 \\ 4 \\ 1 \end{array}\right] \end{array}$$
Verify that \(\lambda_{i}\) is an eigenvalue of \(A\) and that \(\mathbf{x}_{i}\) is a corresponding eigenvector. $$\begin{array}{l} A=\left[\begin{array}{lll} 1 & 1 & 1 \\ 0 & 1 & 0 \\ 1 & 1 & 1 \end{array}\right] ; \quad \lambda_{1}=2, \quad \mathbf{x}_{1}=\left[\begin{array}{l} 1 \\ 0 \\ 1 \end{array}\right] \\ \lambda_{2}=0, \quad \mathbf{x}_{2}=\left[\begin{array}{r} -1 \\ 0 \\ 1 \end{array}\right] ; \quad \lambda_{3}=1, \quad \mathbf{x}_{3}=\left[\begin{array}{r} -1 \\ 1 \\ -1 \end{array}\right] \end{array}$$
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