Chapter 2: Problem 42
find \(A\) provided that $$(4 A)^{-1}=\left[\begin{array}{rr} 2 & 4 \\ -3 & 2 \end{array}\right]$$
Short Answer
Expert verified
The matrix \( A \) is \[\[1/4, -1/2; 3/2, 1/4\]\]
Step by step solution
01
Recall Properties of Matrix Inversion
A key property of matrix inversion is that for any non-singular matrix \( B \) and non-zero scalar \( c \), we have \( (cB)^{-1} = c^{-1}B^{-1} \) . This means that the order of operations are interchangeable for scalar multiplication and matrix inversion.
02
Apply Properties to the Given Matrix
Given that \( (4A)^{-1} \) equals a specific matrix, apply the property. We get that \(A^{-1} = 4\[2,4;-3,2\]\). The matrix has been multiplied by 4 which is the inverse of the scalar originally multiplying \( A \). Now, compute this multiplication.
03
Compute Scalar Multiplication of the Matrix
Calculating, we get \(A^{-1} = \[8,16;-12,8\]\). This is the inverse of matrix \( A \).
04
Find Inverse of the Resulting Matrix
Knowing that \( A^{-1} = \[8,16;-12,8\]\), we can find \( A \) as the inverse of the resulting matrix. The formula for the inverse of a 2x2 matrix \[\[a,b;c,d\]\] is \[\[\frac{d}{ad-bc},\frac{-b}{ad-bc};\frac{-c}{ad-bc},\frac{a}{ad-bc}\]\]
05
calculate the inverse of the matrix obtained in step 3
Substitute a=8, b=16, c=-12, d=8 into the formula: \( A = \[\[1/4, -1/2; 3/2, 1/4\]\] \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Non-Singular Matrix
In the context of linear algebra, a matrix is considered to be non-singular if it has an inverse, meaning there exists another matrix that, when multiplied with the original matrix, yields the identity matrix. Another term for a non-singular matrix is an invertible or non-degenerate matrix.
The importance of a matrix being non-singular cannot be overstated, especially when solving linear equations. For a 2x2 matrix, a simple way to check for singularity is to compute its determinant, which is the value calculated from its elements. The determinant of a 2x2 matrix \( A \), given by \( \left[ \begin{array}{cc} a & b \ c & d \end{array} \right] \) is \( ad - bc \). If this value is zero, the matrix does not have an inverse and is therefore singular.
Only non-singular matrices can perform certain operations, such as finding an eigenvalue or taking advantage of certain matrix decompositions. Therefore, determining the singularity of a matrix is a crucial step before applying matrix inversion.
The importance of a matrix being non-singular cannot be overstated, especially when solving linear equations. For a 2x2 matrix, a simple way to check for singularity is to compute its determinant, which is the value calculated from its elements. The determinant of a 2x2 matrix \( A \), given by \( \left[ \begin{array}{cc} a & b \ c & d \end{array} \right] \) is \( ad - bc \). If this value is zero, the matrix does not have an inverse and is therefore singular.
Only non-singular matrices can perform certain operations, such as finding an eigenvalue or taking advantage of certain matrix decompositions. Therefore, determining the singularity of a matrix is a crucial step before applying matrix inversion.
Scalar Multiplication in Matrices
Scalar multiplication is one of the fundamental operations in matrix algebra. It involves multiplying each entry of a matrix by a fixed number, known as a scalar. For instance, if we have a scalar \( k \) and a matrix \( M \) with elements \( m_{ij} \), the result of scalar multiplication, \( kM \), is a matrix where each element is \( km_{ij} \).
This operation is particularly important when considering the properties of matrix inversion in relation to scalars. When a non-singular matrix is involved, scalar multiplication and inversion can be interchanged due to the distributive property, leading to the equation \( (kM)^{-1} = k^{-1}M^{-1} \).
To make this concept more digestible:
This operation is particularly important when considering the properties of matrix inversion in relation to scalars. When a non-singular matrix is involved, scalar multiplication and inversion can be interchanged due to the distributive property, leading to the equation \( (kM)^{-1} = k^{-1}M^{-1} \).
To make this concept more digestible:
- Imagine you have a tray of cookies arranged in rows and columns, forming a matrix.
- If someone said to double the amount of cookies on each spot of the tray, you would be performing scalar multiplication by 2.
- If the number of cookies were to be then distributed evenly or inversely, dividing by the same scalar would reverse the multiplication.
Inverse of a 2x2 Matrix
Finding the inverse of a 2x2 matrix is a rather direct process, involving a few calculations based on the elements of the matrix. The inverse of a matrix \( A \), denoted as \( A^{-1} \), is the matrix that, when multiplied with \( A \), yields the identity matrix. The identity matrix is like the number 1 in multiplication; it doesn't change the original matrix.
The specific formula for the inverse of a 2x2 matrix is derived from its elements: \( \left[ \begin{array}{cc} a & b \ c & d \end{array} \right]^{-1} = \frac{1}{ad - bc}\left[ \begin{array}{rr} d & -b \ -c & a \end{array} \right] \). Note that this formula only works when the matrix is non-singular, which hinges on the determinant \( ad - bc \) being non-zero.
To illustrate using a numerical example, let’s say you have the matrix \( \left[ \begin{array}{cc} 2 & 5 \ 1 & 3 \end{array} \right] \). To invert this matrix:
The specific formula for the inverse of a 2x2 matrix is derived from its elements: \( \left[ \begin{array}{cc} a & b \ c & d \end{array} \right]^{-1} = \frac{1}{ad - bc}\left[ \begin{array}{rr} d & -b \ -c & a \end{array} \right] \). Note that this formula only works when the matrix is non-singular, which hinges on the determinant \( ad - bc \) being non-zero.
To illustrate using a numerical example, let’s say you have the matrix \( \left[ \begin{array}{cc} 2 & 5 \ 1 & 3 \end{array} \right] \). To invert this matrix:
- First, calculate the determinant: \( 2*3 - 1*5 = 1 \).
- Since the determinant is non-zero, the matrix is non-singular and an inverse exists.
- Next, apply the formula, resulting in \( \left[ \begin{array}{rr} 3 & -5 \ -1 & 2 \end{array} \right] \).
- Finally, multiply each element by \( 1/det(A) \) to get the inverse.