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Consider the system of linear equations in \(x\) and \(y\) \\[ \begin{array}{l} a x+b y=e \\ c x+d y=f \end{array} \\] Under what conditions will the system have exactly one solution?

Short Answer

Expert verified
The system of equations will have exactly one solution when \(ad \neq bc\).

Step by step solution

01

Derive the slopes of the two lines

The slope of a line represented by the equation \(ax + by = e\) is given by \(-a/b\), and that of \(cx + dy = f\) is given by \(-c/d\). Thus, the slopes of the two lines in the system here are \(-a/b\) and \(-c/d\) respectively.
02

Evaluate the condition when the slopes are not equal

For the system to have exactly one solution, the two lines must be non-parallel, which means their slopes must not be equal. Setting \(-a/b \neq -c/d\), which simplifies to \(ad \neq bc\).
03

State the final condition

So the system of equations will have exactly one solution when the condition \(ad \neq bc\) is satisfied. If \(ad = bc\), they will either have infinite solutions (if they coincide) or no solution (if they are parallel).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slopes of Lines
In the context of systems of linear equations, understanding the slopes of lines is crucial. Each linear equation can be represented as a line on a coordinate plane. The slope of a line provides information about its angle of inclination with respect to the x-axis. For a linear equation of the form \(ax + by = e\), the slope is calculated as \(-\frac{a}{b}\). This formula comes from rearranging the equation into the slope-intercept form, \(y = mx + c\), where \(m\) is the slope.

The concept of slope is key when analyzing systems of equations. By calculating the slopes \(-\frac{a}{b}\) for \(ax + by = e\) and \(-\frac{c}{d}\) for \(cx + dy = f\), we can determine if the lines are parallel, identical, or intersecting at a unique point.
Unique Solution
A system of linear equations will have a unique solution when the lines represented by these equations intersect at a single point. This point is where both equations are simultaneously satisfied, and no other points will do the same.

To achieve this unique intersection point, the key is that the lines should be non-parallel. Non-parallel lines are those that have different slopes, ensuring they eventually cross each other somewhere on the graph. In mathematical terms, for our system of equations, the inequality \(-\frac{a}{b} eq -\frac{c}{d}\) or equivalently, \(ad eq bc\), must hold true.

If this condition is met, you can be confident that the system has one and only one solution, as each line will take a different path through the graph.
Conditions for Solvability
The conditions for a system of linear equations to be solvable, specifically to have a unique solution, revolve around the relationship between their coefficients. For the given system:
  • If \(ad eq bc\), the lines intersect at exactly one point, leading to a unique solution.
  • If \(ad = bc\), the situation changes. The lines could be parallel with no points in common, indicating no solutions.
  • Alternatively, if the entire equations are multiples of each other, the lines will overlap perfectly and result in infinitely many solutions.
Understanding this relationship between the coefficients helps in determining whether the set of equations will provide a feasible and unique solution, one that covers specific situations of overlap or parallelism.

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Most popular questions from this chapter

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Consider the \(2 \times 2\) matrix \(\left[\begin{array}{ll}a & b \\ c & d\end{array}\right]\) Perform the sequence of row operations. (a) Add (-1) times the second row to the first row. (b) Add 1 times the first row to the second row. (c) Add (-1) times the second row to the first row. (d) Multiply the first row by (-1) What happened to the original matrix? Describe, in general, how to interchange two rows of a matrix using only the second and third elementary row operations.

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