Chapter 8: Problem 45
For Exercises 45 and \(46,\) use this information: Let \(a, b,\) and \(c\) be the integer lengths of the sides of a triangle. If the area of the triangle is also an integer, then \((a, b, c)\) is known as a Heron triple. Which of these are Heron triples? a) \((5,6,7)\) b) \((13,14,15)\)
Short Answer
Expert verified
(5, 6, 7) is not a Heron triple; (13, 14, 15) is a Heron triple.
Step by step solution
01
Verify if (5,6,7) forms a triangle
For three lengths to form a triangle, they must satisfy the triangle inequality: the sum of any two sides must be greater than the third side.
- For sides 5, 6, and 7:
- 5 + 6 = 11 > 7
- 5 + 7 = 12 > 6
- 6 + 7 = 13 > 5
Therefore, (5, 6, 7) can form a triangle.
02
Determine the semi-perimeter for (5,6,7)
The semi-perimeter, denoted as \( s \), is calculated by \( s = \frac{a + b + c}{2} \).For (5,6,7):\[ s = \frac{5 + 6 + 7}{2} = 9 \]
03
Compute the area using Heron's formula for (5,6,7)
Heron's formula for the area of a triangle is:\[ A = \sqrt{s(s-a)(s-b)(s-c)} \]Substitute the values for (5,6,7):\[ A = \sqrt{9(9-5)(9-6)(9-7)} = \sqrt{9 \times 4 \times 3 \times 2} = \sqrt{216} \]The area \( \sqrt{216} = 6 \sqrt{6} \) which is not an integer.
04
Verify if (13,14,15) forms a triangle
To check if (13, 14, 15) can form a triangle, verify the triangle inequality:
- For sides 13, 14, and 15:
- 13 + 14 = 27 > 15
- 13 + 15 = 28 > 14
- 14 + 15 = 29 > 13
Therefore, (13, 14, 15) can form a triangle.
05
Determine the semi-perimeter for (13,14,15)
The semi-perimeter \( s \) is calculated by:\[ s = \frac{a + b + c}{2} = \frac{13 + 14 + 15}{2} = 21 \]
06
Compute the area using Heron's formula for (13,14,15)
Substitute into Heron's formula:\[ A = \sqrt{21(21-13)(21-14)(21-15)} = \sqrt{21 \times 8 \times 7 \times 6} = \sqrt{7056} \]The area \( \sqrt{7056} = 84 \) is an integer.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Heron's formula
Heron's formula is a magical tool for calculating the area of a triangle when you know the lengths of all three sides. This formula is especially handy because you don't need to know any angles. Here's the formula:\[ A = \sqrt{s(s-a)(s-b)(s-c)} \]where \( A \) is the area of the triangle, and \( s \) is the semi-perimeter of the triangle. The variables \( a \), \( b \), and \( c \) represent the lengths of the sides of the triangle. This formula lets you easily find out if the area is an integer, like in a Heron triple. If it turns out to be an integer, it means the set of numbers can be a candidate for a Heron triple.Using Heron's formula involves a bit of calculation:
- First, find the semi-perimeter \( s \) (we'll explain how in the next section).
- Next, use \( s \) to calculate \( A \).
- Finally, check if \( A \) is an integer.
Triangle inequality
The triangle inequality is a fundamental rule in geometry that helps us verify if three lengths can make a triangle. This rule states that for three lengths to form a triangle, the sum of the lengths of any two sides must be greater than the length of the third side.
Let's check what this means with examples:
- For the triangle with sides (5, 6, 7):
- 5 + 6 = 11, which is greater than 7.
- 5 + 7 = 12, which is greater than 6.
- 6 + 7 = 13, which is greater than 5.
All conditions are satisfied, so (5, 6, 7) can form a triangle. - Similarly, for the sides (13, 14, 15):
- 13 + 14 = 27 is greater than 15.
- 13 + 15 = 28 is greater than 14.
- 14 + 15 = 29 is greater than 13.
Hence, these lengths satisfy the triangle inequality, too.
Semi-perimeter
The semi-perimeter of a triangle is simply half of its perimeter. It's an essential part of Heron's formula and makes working with triangles easier. You calculate it with the formula:\[ s = \frac{a + b + c}{2} \]Here, \( s \) is the semi-perimeter, and \( a \), \( b \), and \( c \) are the side lengths of the triangle.Here's how we use it:
- For the triangle (5, 6, 7):
- \( s = \frac{5 + 6 + 7}{2} = 9 \). - For the triangle (13, 14, 15):
- \( s = \frac{13 + 14 + 15}{2} = 21 \).