Chapter 10: Problem 6
For the line \(\ell:(x, y, z)=(5,-3,2)+n(1,2,-2),\) find a) a point of the line. b) a direction vector for the line.
Short Answer
Expert verified
a) (5, -3, 2) is a point; b) (1, 2, -2) is the direction vector.
Step by step solution
01
Understanding the Line Equation
The line is given by its parametric equation: \( (x, y, z) = (5, -3, 2) + n(1, 2, -2) \). This equation shows a point and a direction vector. It consists of a point (5, -3, 2) and an arbitrary parameter \( n \) which scales the direction vector (1, 2, -2).
02
Identify a Point on the Line
From the parametric equation, \( (x, y, z) = (5, -3, 2) + n(1, 2, -2) \), any specific value of \( n \) will give a point on the line. By setting \( n = 0 \), we simplify the point to \((x, y, z) = (5, -3, 2) \). Thus, \((5, -3, 2)\) is a point on the line.
03
Determine the Direction Vector
The direction vector for a line in parametric form is the coefficient of the parameter \( n \). In the equation \( (x, y, z) = (5, -3, 2) + n(1, 2, -2) \), the direction vector is \((1, 2, -2)\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Direction Vector
In the context of geometry, a direction vector is a fundamental element for any line described using parametric equations. It indicates the line's direction in three-dimensional space. The direction vector is derived from the term that is multiplied by the parameter, often denoted as \( n \), in the parametric equation of a line. For example, in the equation \((x, y, z) = (5, -3, 2) + n(1, 2, -2)\), the term \((1, 2, -2)\) is the direction vector.
A direction vector allows you to understand how a line extends through space. This vector essentially "points" in the direction the line goes, with its components indicating movement along the x, y, and z axes, respectively.
A direction vector allows you to understand how a line extends through space. This vector essentially "points" in the direction the line goes, with its components indicating movement along the x, y, and z axes, respectively.
- The x-component tells you the amount of movement in the x-direction.
- The y-component shows how much the line moves in the y-direction.
- The z-component reveals the movement along the z-axis.
Point on a Line
To find a point on a line that is given in parametric form, you must identify a specific value for the parameter \( n \), which then results in a specific point on the line. Consider the line equation \((x, y, z) = (5, -3, 2) + n(1, 2, -2)\).
When \( n \) is set equal to any specific number, the resulting values give the coordinates of a point on the line. For instance:
When \( n \) is set equal to any specific number, the resulting values give the coordinates of a point on the line. For instance:
- If \( n = 0 \), the point is \((5, -3, 2)\).
- If \( n = 1 \), the point is \((6, -1, 0)\).
- If \( n = -1 \), the point becomes \((4, -5, 4)\).
Line Equation in 3D
The line equation in three-dimensional space finds its form through the parametric representation. Parametric equations, such as \((x, y, z) = (5, -3, 2) + n(1, 2, -2)\), provide a powerful way to describe lines in 3D. These equations involve both a fixed point and a direction vector, alongside a parameter \( n \).
The fixed point, \((5, -3, 2)\) in this example, serves as a base or starting point on the line. Together with the direction vector \((1, 2, -2)\), it enables the expression of any point on the line. By altering \( n \), you can move along the line continuously in either direction, discovering any point you wish.
The fixed point, \((5, -3, 2)\) in this example, serves as a base or starting point on the line. Together with the direction vector \((1, 2, -2)\), it enables the expression of any point on the line. By altering \( n \), you can move along the line continuously in either direction, discovering any point you wish.
- This approach is extremely flexible and clear, making it easy to calculate points.
- It helps in visualizing the line in terms of its orientation in 3D space.
- Parametric equations can also be generalized for use in computer graphics and physics simulations.