/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 16 Find an equation of the line des... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find an equation of the line described. Leave the solution in the form \(A x+B y=C\). The line contains \((b, c)\) and has slope \(d\)

Short Answer

Expert verified
The equation is \( dx - y = db - c \).

Step by step solution

01

Understand the point-slope form

The point-slope form of the equation of a line is \( y - y_1 = m(x - x_1) \), where \( m \) is the slope and \( (x_1, y_1) \) is a point on the line. For our exercise, the point is \((b, c)\) and the slope is \(d\).
02

Substitute point and slope into point-slope equation

Substitute the given point \((b, c)\) and slope \(d\) into the point-slope form: \( y - c = d(x - b) \).
03

Simplify and rearrange into standard form

Expand the equation from step 2: \( y - c = dx - db \). Now rearrange it into the standard form \( Ax + By = C \). Move terms around to get \(-dx + y = c - db\).
04

Multiply both sides to ensure integer coefficients

To put the equation in the ideal standard form \( Ax + By = C \), you may need integer coefficients. If \(-d\) is already an integer, you can multiply the entire equation by \(-1\) to make \( A \) positive if desired. The equation becomes \( dx - y = db - c \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Point-Slope Form
The **point-slope form** is a way to describe the equation of a straight line when you know a single point on the line and its slope. This form is written as:\[y - y_1 = m(x - x_1)\]Where:
  • \( m \) is the slope of the line.
  • \((x_1, y_1)\) is a known point on the line.
This formula comes in handy, especially when you don't know the y-intercept but have other details.
Let's say you have a line passing through the point \((b, c)\) with a known slope \(d\).
By plugging these values into the point-slope equation, you get:\[y - c = d(x - b)\]This is an intermediate step in converting to other forms of linear equations. It helps build connections between the point, the slope, and the behavior of the line.
Slope-Intercept Form
The **slope-intercept form** of a line's equation is one of the simplest and most popular ways to express a linear equation.This form is written as:\[y = mx + b\]Where:
  • \( m \) is still the slope of the line.
  • \( b \) is the y-intercept, which is the point where the line crosses the y-axis.
By knowing the slope and y-intercept, you can plot the entire line on a graph. For our purposes, you can rearrange a point-slope equation into this form if needed.
Starting from the point-slope equation, for example:\[y - c = d(x - b)\]Solve for \( y \), and you'll end up with the slope-intercept form. Even though this is not always necessary for getting to standard form, it's a useful stepping stone for visualizing the line quickly.
Standard Form of a Line
The **standard form** of a line's equation is another common format, different from the others in that it focuses on organizing the terms naturally and neatly:\[Ax + By = C\]Where:
  • \( A \), \( B \), and \( C \) are integers.
  • \( A \) is non-negative, and both \( A \) and \( B \) are not both zero.
Starting from the point-slope form of our exercise:\[y - c = d(x - b)\]We rearrange this into standard form by moving all terms involving \(x\) and \(y\) to one side, and constant terms to the other side. The results are equations like \(-dx + y = c - db\).
In cases where the coefficients aren't integers, multiply every term to eliminate fractions. You might prefer a positive \( A \), so multiplying the equation by \(-1\) might do the trick if needed. This ensures our answer isn't only correct but also "clean" and easy to interpret.

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