Chapter 9: Problem 18
Find the total area (surface area) of a regular tetrahedron if each edge has a length of 6 in.
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Chapter 9: Problem 18
Find the total area (surface area) of a regular tetrahedron if each edge has a length of 6 in.
These are the key concepts you need to understand to accurately answer the question.
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Make drawings as needed. Can two spheres a) be internally tangent? b) have no points in common?
Find the approximate surface area and volume of the sphere if \(O P=6\) in. Use your calculator.
Use the fact that \(r^{2}+h^{2}=\ell^{2}\) in a right circular cone (Theorem 9.3.6). A triangle has sides that measure \(15 \mathrm{cm}, 20 \mathrm{cm},\) and \(25 \mathrm{cm} .\) Find the exact volume of the solid of revolution formed when the triangle is revolved about the side of length \(15 \mathrm{cm}\)
In sphere \(O\), the length of radius \(O P\) is 6 in. Find the length of the chord: a) \(Q R\) if \(\mathrm{m} \angle Q O R=90^{\circ}\) b) \(\overline{Q S}\) if \(\mathrm{m} \angle S O P=60^{\circ}\) (sphere can't copy)
The foyer planned as an addition to an existing church is designed as a regular octagonal pyramid. Each side of the octagonal floor has a length of \(10 \mathrm{ft}\), and its apothem measures 12 ft. If \(800 \mathrm{ft}^{2}\) of plywood is needed to cover the exterior of the foyer (that is, the lateral area of the pyramid is \(800 \mathrm{ft}^{2}\) ), what is the height of the foyer?
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