/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 9 Find the equation of the line de... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the equation of the line described. Leave the solution in the form \(A x+B y=C\). The line has slope \(m=-\frac{2}{3}\) and contains \((0,5)\).

Short Answer

Expert verified
The equation of the line is \(2x + 3y = 15\).

Step by step solution

01

Identify the Given Information

We are provided with a slope, \(m = -\frac{2}{3}\), and a point on the line, \((0,5)\). The point indicates that when \(x = 0\), \(y = 5\).
02

Use Point-Slope Form

The point-slope form of the equation of a line is \(y - y_1 = m(x - x_1)\). Here, \((x_1, y_1)\) is the given point, which is \((0, 5)\), and \(m\) is the slope. So, the equation becomes: \[y - 5 = -\frac{2}{3}(x - 0)\]
03

Simplify the Equation

Simplify the equation obtained from the point-slope form.\[y - 5 = -\frac{2}{3}x\] Add 5 to both sides to isolate \(y\): \[y = -\frac{2}{3}x + 5\]
04

Convert to Standard Form \(Ax + By = C\)

To convert the equation to standard form, eliminate the fraction by multiplying the entire equation by 3:\[3y = -2x + 15\] Rearrange to get \(Ax + By = C\): \[2x + 3y = 15\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope
The slope of a line is a measure of its steepness and direction. It is denoted by the letter "m." In the context of a linear equation, the slope tells us how much the y-coordinate changes for a change in the x-coordinate. The formula for slope is given by:
  • \( m = \frac{\text{rise}}{\text{run}} = \frac{y_2 - y_1}{x_2 - x_1} \)
For the line in our problem, the slope is \( m = -\frac{2}{3} \), which means that for every 3 units the line moves horizontally, it descends by 2 units vertically.
The sign of the slope indicates the direction of the line. A negative slope, like in this case, means the line is decreasing. The line will slant downwards as we move from left to right.
Point-Slope Form
The point-slope form of a linear equation is a powerful tool that helps us write the equation of a line when we're given the slope and one point on the line. The form is:
  • \( y - y_1 = m(x - x_1) \)
Here, \((x_1, y_1)\) is a known point, and \(m\) is the slope.
This formula is particularly useful when you need to find the equation of a line quickly without having to solve for the y-intercept explicitly. In the exercise, we utilize \((0,5)\) as our point \((x_1, y_1)\) and the slope \(-\frac{2}{3}\) to form:
  • \( y - 5 = -\frac{2}{3}(x - 0) \)

Simplifying leads us to a more straightforward linear expression, which is then easily converted into its other forms.
Standard Form
A linear equation in standard form is expressed as \( Ax + By = C \). Each of these represents integers, with \(A\) typically being non-negative. This form is particularly useful for quickly identifying intercepts and establishing the relationships between variables.
To transform an equation from another form, like slope-intercept, into standard form:
  • Begin by clearing any fractions (often by multiplying through by the denominator).
  • Rearrange terms to align with \( Ax + By = C \).

In our problem, converting \( y = -\frac{2}{3}x + 5 \) involved multiplying the equation by 3 to clear the fraction and then rearranging to
  • \( 2x + 3y = 15 \)

This conversion makes it easier to analyze and graph the equation.
Linear Equation
A linear equation forms a straight line when graphed on the coordinate plane. These equations are fundamental in algebra and have the general form of \( y = mx + b \), where \(m\) is the slope and \(b\) is the y-intercept.
Linear equations can be used in various forms:
  • Slope-Intercept Form: \( y = mx + b \)
  • Point-Slope Form: \( y - y_1 = m(x - x_1) \)
  • Standard Form: \( Ax + By = C \)

Each form serves different purposes; slope-intercept is great for graphing, point-slope is excellent for quickly writing an equation from a point and slope, and standard form is ideal for systems of equations. In this exercise, we start with the point-slope form and derive the standard form, demonstrating how different conditions dictate which form is most useful.

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