Chapter 6: Problem 9
Suppose that \((X, \mathscr{F})\) is a measure space and \(E: \mathscr{F} \rightarrow \mathscr{B}(\mathscr{H})\) is a spectral measure. Show that if \(f_{1}\) and \(f_{2}\) are bounded measurable functions on \(X\) with \(f_{1}(x)=\) \(f_{2}(x)\) for all \(x\) in some carrier \(C\) for \(E\), then $$ \int f_{1} d E=\int f_{2} d E . $$
Short Answer
Step by step solution
Define the Integral Over a Spectral Measure
Understand the Concept of a Carrier
Consider the Equality on the Carrier
Use the Property of the Integral with Respect to Spectral Measures
Conclude the Equality of the Integrals
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Measure Space
- \
- \(X\) is a set, often interpreted as a space where events occur or elements reside. \
- \(\mathscr{F}\) is a sigma-algebra on \(X\), a collection of subsets of \(X\) including the empty set, closed under complementation and countable unions. \
- \(\mu\) is a measure, a function assigning non-negative real numbers or infinity to the sets in \(\mathscr{F}\), respecting the countable additivity property. \
Integral Over a Spectral Measure
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- For a bounded measurable function \(f\), the integral \(\int f \ dE \) is understood through the spectral theorem. \
- The process constructs an operator from simple functions that approximate \(f\), analogous to how definite integrals approximate cumulative distribution functions. \
Carrier Set
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- The measure outside this subset is \( E(X \setminus C) = 0 \). \
- This ensures that operations, like integration over \(E\), only need to consider what happens within \(C\). \
Bounded Measurable Functions
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- \(f\) is measurable if, for every real number, the pre-image of all intervals of the form \(( -\infty, a ]\) is within the sigma-algebra \(\mathscr{F}\). \
- Functions satisfying these conditions are integral over spectral measures, as they ensure that approximations converge uniformly. \