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Consider the operator on \(\ell^{\infty}\) defined by $$ T\left(x_{1}, x_{2}, \ldots\right)=\left(\lambda_{1} x_{1}, \lambda_{2} x_{2}, \ldots\right) $$ where \(\left(\lambda_{1}, \lambda_{2}, \ldots\right)\) is in \(\ell^{\infty}\). Find \(\sigma_{p}(T), \sigma(T)\) and show that \(\sigma(T) \backslash \sigma_{p}(T)\) is the residual spectrum of \(T\).

Short Answer

Expert verified
\(\sigma_p(T) = \{ \lambda_i \}, \sigma(T) = \overline{\{ \lambda_i \}}, \sigma(T) \backslash \sigma_p(T)\) is the residual spectrum.

Step by step solution

01

Define the Spectrum

The spectrum of an operator \(T\), denoted \(\sigma(T)\), consists of all \(\lambda \in \mathbb{C}\) such that \(T - \lambda I\) is not invertible. The set \(\sigma(T)\) can be divided into the point spectrum \(\sigma_p(T)\), the continuous spectrum, and the residual spectrum.
02

Find the Point Spectrum \(\sigma_{p}(T)\)

The point spectrum \(\sigma_p(T)\) consists of all \(\lambda\) for which \(T - \lambda I\) is not injective. This means there exists some non-zero sequence \((x_{1}, x_{2}, \ldots)\) such that \(T(x) = \lambda x\). In our case, this leads to the requirement \((\lambda_{i} - \lambda)x_{i} = 0\) for all \(i\), implying \(\lambda_{i} = \lambda\) for some \(i\), for non-zero \(x_i\). Thus, \(\sigma_p(T) = \{ \lambda_i : i \in \mathbb{N}\}\).
03

Determine the Spectrum \(\sigma(T)\)

The spectrum \(\sigma(T)\) includes \( \lambda \) values that prevent \(T - \lambda I\) from being invertible. This includes the point spectrum \(\sigma_p(T)\), and for this specific operator, any \(\lambda\) that satisfies the condition \(\sup |\lambda_i - \lambda| = 0\), meaning \(\lambda\) is a limit point of the sequence \((\lambda_i)\), or \(\lambda\) is equal to one of the \(\lambda_i\). Thus, \(\sigma(T) = \overline{\{\lambda_i \}}\), the closure of the sequence.
04

Identify the Residual Spectrum

The residual spectrum consists of \(\lambda\) such that \(T - \lambda I\) is injective but not surjective. This means \(\lambda\) is not an eigenvalue (not in \(\sigma_p(T)\)), but still in \(\sigma(T)\). Since the operator is defined on \(\ell^{\infty}\) where each \(\lambda_i\) can be bounded, the residual spectrum \(\sigma(T) \backslash \sigma_p(T)\) consists of the limit points of \(\{\lambda_i\}\) not included in the sequence itself.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spectral Theory
Spectral theory is a fundamental branch of operator theory and functional analysis that studies the spectrum of operators. The spectrum of an operator, denoted as \( \sigma(T) \), is essentially the set of values that describe how an operator behaves on a given space.

In the context of a linear operator \( T \) acting on a space like \( \ell^{\infty} \), the spectrum includes several components:
  • The point spectrum, \( \sigma_p(T) \), includes all eigenvalues—these are \( \lambda \) values for which \( T - \lambda I \) fails to be injective.
  • The residual spectrum comprises \( \lambda \) where \( T - \lambda I \) is injective but not surjective.
  • The continuous spectrum includes values where \( T - \lambda I \) is not invertible yet does not belong to the other spectrum types.
Understanding the spectrum provides insights into the operator's properties and behaviors. In the case of our operator in \( \ell^{\infty} \), the closure operation \( \overline{\{\lambda_i\}} \) helps identify the full spectrum, which includes the limit points along with the eigenvalues.
Functional Analysis
Functional analysis is an area of mathematics primarily concerned with studying functions, spaces, and operators. It provides the framework for understanding various types of infinities, transformations, and relationships in complex mathematical spaces.

Operators like \( T \) on spaces such as \( \ell^{\infty} \) are key subjects of study in this field.
  • Banach spaces, like \( \ell^{\infty} \), offer a complete normed vector space. In these spaces, all Cauchy sequences converge, which is crucial for analyzing bounded operators.
  • Linear operators are functions mapping between vector spaces, preserving vector addition and scalar multiplication. An operator's properties, such as being bounded or compact, are central to functional analysis.
Applying functional analysis to operators helps determine behaviors, understand convergence, and explore how different types of spectra arise from an operator's action on spaces.
Bounded Operators
Bounded operators are a crucial concept in both functional analysis and operator theory. A bounded operator on a Banach space, such as \( \ell^{\infty} \), preserves boundedness, meaning it maps bounded sets to bounded sets consistently.

Importantly, bounded operators between normed spaces retain continuity:
  • An operator \( T \) is considered bounded if there exists a constant \( M \) such that \| T(x) \| \leq M \| x \| for all vectors \( x \).
  • This ensures that no matter how large or small the input is, the output remains within a predictable range of values.
In our problem, the constraints provided by the bounded nature of the sequence \( (\lambda_1, \lambda_2, \ldots) \) in \( \ell^{\infty} \) are fundamental in determining both the point and residual spectra. Boundedness guarantees that the operator doesn't exhibit any 'wild' behavior and allows deeper exploration of its spectral properties.

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Most popular questions from this chapter

Suppose \(\mathscr{A}\) and \(\mathscr{B}\) are Banach algebras with common identity and \(\mathscr{B} \subseteq \mathscr{A}\). Show \(\sigma_{\mathscr{I}}(A) \subseteq \sigma_{\mathscr{B}}(A)\) and \(\partial \sigma_{\mathscr{D}}(A) \subseteq \partial \sigma_{\mathscr{I}}(A)\), for any \(A \in \mathscr{B}\). Hint for the second part: Since the first part implies that the interior of \(\sigma_{\sigma f}(A)\) is contained in the interior of \(\sigma_{\mathscr{B}}(A)\) for any \(A\) in \(\mathscr{B}\), argue first that it suffices to show that if \(\lambda \in \partial \sigma_{\mathscr{D}}(A)\), then \(\lambda \in \sigma_{\sigma d}(A)\).

Let \(\mathscr{G}\) denote the set of invertible elements in a unital Banach algebra. Show that the map of \(\mathscr{G}\) into \(\mathscr{G}\) defined by \(A \rightarrow A^{-1}\) is continuous.

Let \(\mathscr{A}\) be a unital commutative Banach algebra, and suppose \(A, B \in \mathscr{A}\). Show that \(r(A+B) \leq r(A)+r(B)\) and \(r(A B) \leq r(A) r(B)\). (Hint: Use the Gelfand transform.) Show the same result holds if \(\mathscr{A}\) is not assumed to be commutative, provided \(A B=B A\). Show the result fails in general (look in \(\left.M_{2}(\mathbb{C})\right)\).

Suppose that \(P\) and \(Q\) are orthogonal projections onto closed subspaces \(M\) and \(N\) in \(\mathscr{H}\), respectively. Show that \(P \geq Q\) if and only if \(N \subseteq M\).

Show that a Banach algebra \(\mathscr{A}\) with an involution satisfying $$ \left\|A^{*} A\right\| \geq\|A\|^{2} $$ is a \(C^{*}\)-algebra, meaning that equality holds in this inequality.

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