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(a) Show that for a normed linear space \(X\), the map \(x \rightarrow\|x\|\) of \(X\) into \([0, \infty)\) is continuous. Is it uniformly continuous? (b) Show that the mappings \(X \times X \rightarrow X\) given by \((x, y) \rightarrow x+y\), and \(\mathbb{C} \times X \rightarrow X\) given by \((\alpha, x) \rightarrow \alpha x\) are continuous. The topologies on \(X \times X\) and \(\mathbb{C} \times X\) are the product topologies. (c) Suppose that \(X\) is an inner product space. Show that the maps \(x \rightarrow\langle x, y\rangle\) and \(x \rightarrow\) \(\langle y, x\rangle\) are continuous on \(X\) for each fixed \(y\) in \(X\). Are they uniformly continuous?

Short Answer

Expert verified
The norm map is continuous but not uniformly continuous. Addition and scalar multiplication are continuous. Inner product maps are continuous but not uniformly continuous.

Step by step solution

01

Prove Continuity of Norm Function

To prove that the map \( x \rightarrow \|x\| \) is continuous for a normed linear space \( X \), assume a sequence \( \{ x_n \} \) in \( X \) such that \( x_n \rightarrow x \). Then by the properties of the norm, we have \( \|x_n - x\| \rightarrow 0 \). According to the triangle inequality, \( |\|x_n\| - \|x\|| \leq \|x_n - x\| \). Thus, \( |\|x_n\| - \|x\|| \rightarrow 0 \), which implies \( \|x_n\| \rightarrow \|x\| \). Therefore, the norm function is continuous.
02

Evaluate Uniform Continuity of Norm Function

For the norm function to be uniformly continuous, the difference \( \|x - y\| \) should be small whenever \( \|x - y\| \) is small for any \( x, y \) in \( X \). However, the behavior of \( \|x\| \) solely depends on \( x \), not on a 'global' perspective like in compact spaces. Thus, the norm function is not uniformly continuous on an infinite dimensional space.
03

Prove Continuity of Addition Mapping

Consider the map \( (x, y) \rightarrow x+y \) with product topology on \( X \times X \). Assume \( (x_n, y_n) \rightarrow (x, y) \). This means \( x_n \rightarrow x \) and \( y_n \rightarrow y \). By linearity and limit properties, \( x_n + y_n \rightarrow x + y \). Thus, this mapping is continuous.
04

Prove Continuity of Scalar Multiplication

Consider the map \( (\alpha, x) \rightarrow \alpha x \) with the product topology on \( \mathbb{C} \times X \). Assume \( (\alpha_n, x_n) \rightarrow (\alpha, x) \). This implies \( \alpha_n \rightarrow \alpha \) and \( x_n \rightarrow x \). By the property of limits and scalar multiplication, \( \alpha_n x_n \rightarrow \alpha x \). Hence, the mapping is continuous.
05

Prove Continuity of Inner Product Mapping

Consider the map \( x \rightarrow \langle x, y \rangle \) for a fixed \( y \) in an inner product space \( X \). Assume \( x_n \rightarrow x \). Then \( \langle x_n, y \rangle \rightarrow \langle x, y \rangle \) by the continuity of the inner product with respect to its first variable. Similarly, the map \( x \rightarrow \langle y, x \rangle \) is continuous by considering the second variable.
06

Evaluate Uniform Continuity of Inner Product Mapping

For uniform continuity, both mappings \( x \rightarrow \langle x, y \rangle \) and \( x \rightarrow \langle y, x \rangle \) would require \( \langle x_1 - x_2, y \rangle \) to be small for any \( x_1, x_2 \). This is not guaranteed in general for infinite dimensions, hence these maps are not uniformly continuous without further assumptions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Normed Linear Space
In Functional Analysis, a **Normed Linear Space** is a fundamental concept. It combines the structures of a linear space (or vector space) with a norm, which is a mathematical function that assigns a non-negative length or size to each vector in the space. A norm denoted as \( \|x\| \) must satisfy three properties:
  • \( \|x\| = 0 \) if and only if \( x = 0 \)
  • \( \|\alpha x\| = |\alpha| \cdot \|x\| \) for any scalar \( \alpha \)
  • Triangle inequality: \( \|x + y\| \leq \|x\| + \|y\| \)
These properties enable us to measure distances and angles, which is crucial for many mathematical and applied disciplines. The continuity of the norm function \( x \rightarrow \|x\| \) is a key topic in analysis. It can be shown that this function is continuous. By considering a convergent sequence \( \{x_n\} \) in the space, the limit properties ensure that \( \|x_n\| \rightarrow \|x\| \) as \( x_n \rightarrow x \). However, the norm function is not uniformly continuous on infinite dimensional spaces, highlighting an important distinction in infinite versus finite-dimensional analysis.
Continuity in Mathematics
**Continuity** is a central idea in mathematics, related to how functions behave under small perturbations. For a function \( f \), continuity at a point implies that for every small change in input, there's a correspondingly small change in the output. This intuitive idea is mathematically captured by limits; formally, \( f(x) \) is continuous at point \( a \) if:\[\lim_{x \to a} f(x) = f(a)\]Continuity is critical for ensuring the function's predictable behavior and is foundational for calculus and real analysis. In the context of normed spaces, maps like addition \((x, y) \rightarrow x+y\), and scalar multiplication \((\alpha, x) \rightarrow \alpha x\), are shown to be continuous functions. By leveraging the properties of limits and the linearity inherent in vector spaces, these mappings preserve the structure under the operation of convergence. Although these maps are continuous, uniform continuity is generally not met in infinite dimensions without additional conditions, reflecting broader nuances in functional spaces.
Inner Product Space
An **Inner Product Space** is an extension of a normed space where an additional structure, the inner product, is defined. This inner product, usually denoted \(\langle x, y \rangle\), not only gives rise to a norm via \(\|x\| = \sqrt{\langle x, x \rangle}\) but also allows the definition of angles and orthogonality between vectors.Key properties of an inner product include:
  • Linearity in the first argument: \( \langle ax + by, z \rangle = a\langle x, z \rangle + b\langle y, z \rangle \)
  • Conjugate symmetry: \( \langle x, y \rangle = \overline{\langle y, x \rangle} \)
  • Positive-definiteness: \( \langle x, x \rangle \geq 0 \) and equals zero if and only if \( x = 0 \)
In an inner product space, mappings such as \( x \rightarrow \langle x, y \rangle \) and \( x \rightarrow \langle y, x \rangle \) are naturally continuous, confirmed by their relation to the boundedness of linear operators. However, these mappings do not guarantee uniform continuity in infinite dimensions, which ties back to the underlying topology and dimensions of the space.
Product Topology
A **Product Topology** describes how topologies can be combined in a product space, typically formed as \( X \times Y \). The fundamental idea is that a basis for the product topology consists of all products of open sets from each space.This relates to continuity in functions involving multiple variables. For instance, consider mappings within a product topology like \( (x, y) \rightarrow x+y \) or scalar multiplication \( (\alpha, x) \rightarrow \alpha x \). These maps are continuous due to the property that the convergence of pairs \((x_n, y_n)\) in product topology implies the convergence of each component separately, making compound operations predictable and coherent. The beauty of product topology lies in its ability to blend different spaces' properties while ensuring that multi-variable operations within these spaces behave well under the topology's structure. Still, while product topology supports continuity, achieving uniform continuity remains more nuanced across differing dimensions and contexts.

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Most popular questions from this chapter

In this problem we describe the Gram-Schmidt process: Let \(x_{1}, x_{2}, \ldots\) be a sequence of linearly independent vectors in an inner product space. Define vectors inductively by $$ \begin{gathered} e_{1}=x_{1} /\left\|x_{1}\right\| \\ f_{n}=x_{n}-\sum_{j=1}^{n-1}\left\langle x_{n}, e_{j}\right\rangle e_{j} \text { for } n \geq 2 \\ e_{n}=f_{n} /\left\|f_{n}\right\| \text { for } n \geq 2 . \end{gathered} $$ Show that \(\left\\{e_{n}\right\\}\) is an orthonormal sequence with the property that the linear span of \(\left\\{x_{1}, x_{2}, \ldots, x_{n}\right\\}\) is the same as the linear span of \(\left\\{e_{1}, e_{2}, \ldots, e_{n}\right\\}\) for each \(n\).

Let \(C^{1}[0,1]\) be the space of continuous, complex-valued functions on \([0,1]\) with continuous first derivative. Show that in the supremum norm \(\|\cdot\|_{\infty}, C^{1}[0,1]\) is not a Banach space, but that in the norm defined by \(\|f\|=\|f\|_{\infty}+\left\|f^{\prime}\right\|_{\infty}\) it does become a Banach space.

Show that in any normed linear space where the norm satisfies the parallelogram equality, an inner product can be defined which induces the norm in the usual sense that \(\langle x, x\rangle=\|x\|^{2}\). Hints: Define \(\langle x, y\rangle\) by polarization and show that \(\langle x, y\rangle=\overline{\langle y, x\rangle}\). Next show that \(\langle x+y, z\rangle=\langle x, z\rangle+\langle y, z\rangle\) by showing the equality of the real parts and imaginary parts of both sides of this identity separately. Finally, show that \(\langle s x, y\rangle=s\langle x, y\rangle\) for \(s\) in turn an integer, a rational number, a real number and a complex number.

Let \(\Lambda: X \rightarrow \mathbb{C}\) be a bounded linear functional on a normed linear space \(X\). Recall that \(\|\Lambda\|\) is defined as \(\sup \\{|\Lambda(x)|:\|x\| \leq 1\\}\). Show that $$ \begin{aligned} \|\Lambda\| &=\sup \\{|\Lambda(x)|:\|x\|=1\\} \\ &=\sup \\{|\Lambda(x)| /\|x\|: x \neq 0\\} \\ &=\inf \\{\delta:|\Lambda(x)| \leq \delta\|x\| \text { for all } x \in X\\} \end{aligned} $$

Show that \(C[0,1]\) is a Banach space in the supremum norm. Hint: If \(\left\\{f_{n}\right\\}\) is a Cauchy sequence in \(C[0,1]\), then for each fixed \(x \in[0,1],\left\\{f_{n}(x)\right\\}\) is a Cauchy sequence in \(\mathbb{C}\), which is complete.

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