Chapter 5: Problem 9
Find the inverse Laplace transform. $$F(s)=\frac{2}{s-3}$$
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Chapter 5: Problem 9
Find the inverse Laplace transform. $$F(s)=\frac{2}{s-3}$$
These are the key concepts you need to understand to accurately answer the question.
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Find the inverse Laplace transform. $$F(s)=\frac{4 s^{2}+s+1}{s^{3}+s}$$
Use the Laplace transform to solve the initial value problem. $$y^{\prime \prime}+4 y=\sin 2 t, \quad y(0)=1, \quad y^{\prime}(0)=0$$
Give the form of the partial fraction expansion for the given rational function \(F(s)\). You need not evaluate the constants in the expansion. However, if the denominator of \(F(s)\) contains irreducible quadratic factors of the form \(s^{2}+2 \alpha s+\beta^{2}, \beta^{2}>\alpha^{2}\), complete the square and rewrite this factor in the form \((s+\alpha)^{2}+\omega^{2}\). $$F(s)=\frac{2 s+3}{(s-1)(s-2)^{2}}$$
Compute the Laplace transform of the given matrix-valued function \(\mathbf{y}(t)\). \(\mathbf{y}(t)=\left[\begin{array}{c}\cos t \\ t \\ t e^{t}\end{array}\right]\)
Assume a body of mass \(m\) moves along a horizontal surface in a straight line with velocity \(v(t)\). The body is subject to a frictional force proportional to velocity and is propelled forward with a periodic propulsive force \(f(t)\). Applying Newton's second law, we obtain the following initial value problem: $$m v^{\prime}+k v=f(t), \quad t \geq 0, \quad v(0)=v_{0} .$$ Assume that \(m=1 \mathrm{~kg}, k=1 \mathrm{~kg} / \mathrm{s}\), and \(v_{0}=1 \mathrm{~m} / \mathrm{s}\). (a) Use Laplace transform methods to determine \(v(t)\) for the propulsive force \(f(t)\), where \(f(t)\) is given in newtons. (b) Plot \(v(t)\) for \(0 \leq t \leq 10\) [this time interval spans the first five periods of \(f(t)\) ]. In Exercise 17, explain why \(v(t)\) is constant on the interval \(0 \leq t \leq 1\). $$ f(t)=t / 2, \quad 0 \leq t<2, \quad f(t+2)=f(t) $$
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