Chapter 5: Problem 12
Find the inverse Laplace transform. $$F(s)=\frac{2 s-3}{s^{2}-3 s+2}$$
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Chapter 5: Problem 12
Find the inverse Laplace transform. $$F(s)=\frac{2 s-3}{s^{2}-3 s+2}$$
These are the key concepts you need to understand to accurately answer the question.
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Use the Laplace transform to solve the initial value problem. $$y^{\prime}-3 y=e^{3 t}, \quad y(0)=1$$
Use Table \(5.1\) to find \(\mathcal{L}^{-1}\\{F(s)\\}\) for the given \(F(s)\). \(F(s)=\frac{5}{(s-3)^{4}}\)
Give the form of the partial fraction expansion for the given rational function \(F(s)\). You need not evaluate the constants in the expansion. However, if the denominator of \(F(s)\) contains irreducible quadratic factors of the form \(s^{2}+2 \alpha s+\beta^{2}, \beta^{2}>\alpha^{2}\), complete the square and rewrite this factor in the form \((s+\alpha)^{2}+\omega^{2}\). $$F(s)=\frac{s^{3}-1}{\left(s^{2}+1\right)^{2}(s+4)^{2}}$$
Find the inverse Laplace transform. $$F(s)=\frac{4 s+5}{s^{2}+9}$$
Use Laplace transforms to solve the given initial value problem. \(\mathbf{y}^{\prime}=\left[\begin{array}{rr}1 & 4 \\ -1 & 1\end{array}\right] \mathbf{y}+\left[\begin{array}{c}0 \\ 3 e^{t}\end{array}\right], \quad \mathbf{y}(0)=\left[\begin{array}{l}3 \\ 0\end{array}\right]\)
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