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Chapter 3: Problem 28

The position of a certain undamped spring-mass system satisfies the initial value problem $$ u^{\prime \prime}+2 u=0, \quad u(0)=0, \quad u^{\prime}(0)=2 $$ (a) Find the solution of this initial value problem. (b) Plot \(u\) versus \(t\) and \(u^{\prime}\) versus \(t\) on the same axes. (c) Plot \(u^{\prime}\) versus \(u ;\) that is, plot \(u(t)\) and \(u^{\prime}(t)\) parametrically with \(t\) as the parameter. This plot is known as a phase plot and the \(u u^{\prime}\) -plane is called the phase plane. Observe that a closed curve in the phase plane corresponds to a periodic solution \(u(t) .\) What is the direction of motion on the phase plot as \(t\) increases?

Short Answer

Expert verified
Answer: The solution of the initial value problem is \(u(t) = \sqrt{2}\sin{\sqrt{2}t}\). The position function, \(u(t)\), is sinusoidal with a period of \(2\pi/\sqrt{2}\) and the velocity function, \(u'(t) = -2\cos{\sqrt{2}t}\), is also sinusoidal with the same period. The graphs of these functions show oscillatory behavior versus time.

Step by step solution

01

Defining the Differential Equation

The given initial value problem is described by the following second-order linear homogeneous differential equation with constant coefficients: $$ u^{\prime\prime} + 2u = 0 $$ Subject to the following initial conditions: $$ u(0) = 0 \\ u'(0) = 2 $$
02

Finding the Complementary Function

To find the complementary function, we assume a solution of the form \(u(t) = e^{rt}\). Substituting this into the differential equation yields: $$ r^2e^{rt} + 2e^{rt} = 0 $$ Dividing through by \(e^{rt}\), we get: $$ r^2 + 2 = 0 $$ Solving for r: $$ r = 卤\sqrt{-2} = 卤i\sqrt{2} $$ This gives us the complementary function of the form: $$ u_c(t) = C_1\cos{\sqrt{2}t} + C_2\sin{\sqrt{2}t} $$ Where \(C_1\) and \(C_2\) are constants to be determined.
03

Applying Initial Conditions

We have the complementary function: $$ u_c(t) = C_1\cos{\sqrt{2}t} + C_2\sin{\sqrt{2}t} $$ Taking the derivative to find u'(t) : $$ u'(t) = -C_1\sqrt{2}\sin{\sqrt{2}t} + C_2\sqrt{2}\cos{\sqrt{2}t} $$ Now, we apply the initial conditions \(u(0)=0\) and \(u'(0)=2\): $$ u(0) = C_1\cos(0) + C_2\sin(0) = 0 \implies C_1 = 0 \\ u'(0) = -C_1\sqrt{2}\sin(0) + C_2\sqrt{2}\cos(0) = 2 \implies C_2 = \frac{2}{\sqrt{2}} = \sqrt{2} $$ Thus, the solution of the initial value problem is: $$ u(t) = \sqrt{2}\sin{\sqrt{2}t} $$
04

Plotting Graphs

(a) The position function of the spring is given by \(u(t) = \sqrt{2}\sin{\sqrt{2}t}\). This function is sinusoidal with a period of \(2\pi/\sqrt{2}\). Graph this function for the position versus time. (b) The velocity function of the spring is given by \(u'(t) = -2\cos{\sqrt{2}t}\). This function is also sinusoidal with a period of \(2\pi/\sqrt{2}\). Graph this function for the velocity versus time on the same axes as u(t) versus time.
05

Creating the Phase Plot

To create the phase plot, we parametrically plot the position \(u(t) = \sqrt{2}\sin{\sqrt{2}t}\) and velocity \(u'(t)=-2\cos{\sqrt{2}t}\) with respect to time. The phase plot is a closed curve as the position and velocity functions are periodic. As t increases, the motion direction on the phase plot is clockwise.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Differential Equations
Differential equations are mathematical equations that describe the relationship between a function and its derivatives. They play a crucial role in modeling the behavior of natural systems, such as the motion of a spring-mass system.

A simple yet important type of differential equation is the second-order linear homogeneous differential equation with constant coefficients. In the context of the exercise, the equation is \( u'' + 2u = 0 \), representing the movement of an undamped spring-mass system.

To solve such an equation, we look for a complementary function, which typically takes the form of an exponential function. Through this approach, constants and the structure of the solution are derived, leading to a function that describes the system's position over time. The method requires the application of initial conditions to find specific values for the constants, thereby arriving at the exact solution that satisfies the problem's requirements.
Deciphering the Phase Plot
A phase plot is a graphical representation that showcases the relationship between a system's state variables, often position and velocity. It is especially useful in visualizing the behavior of dynamical systems.

In the exercise at hand, the phase plot is created by parametrically plotting the position function \(u(t)\) and its derivative \(u'(t)\) over time. The result is a closed curve that reflects the periodicity of the system. A closed curve in the phase plot confirms that a function, in this case \(u(t)\), is periodic.

The Direction of Motion

The direction of the motion on the phase plot, which is clockwise in our example, gives insights into the energy conservation and the system's stability. Observing this plot helps in understanding how the system evolves over time without delving into the specifics of temporal evolution.
The Sinusoidal Function and its Properties
Sinusoidal functions are a cornerstone of mathematics when modeling oscillations and waves. These functions, including the sine and cosine functions, describe smooth periodic oscillations.

In the given spring-mass system described by \(u(t) = \sqrt{2}\sin(\sqrt{2}t)\), the solution represents a sinusoidal function that models the periodic displacement of the spring. Such functions have a set of important properties, including amplitude, period, and frequency, which dictate the behavior of the wave.

Sinusoidal functions are particularly important because they can be used to represent complex oscillatory behavior through simple, uniform equations. By understanding and analyzing the solution in the form of a sinusoidal function, students can predict how the spring system will act over time鈥攔ising and falling in a consistent, repeatable pattern.

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Most popular questions from this chapter

Consider the forced but undamped system described by the initial value problem $$ u^{\prime \prime}+u=3 \cos \omega t, \quad u(0)=0, \quad u^{\prime}(0)=0 $$ (a) Find the solution \(u(t)\) for \(\omega \neq 1\). (b) Plot the solution \(u(t)\) versus \(t\) for \(\omega=0.7, \omega=0.8,\) and \(\omega=0.9\). Describe how the response \(u(t)\) changes as \(\omega\) varies in this interval. What happens as \(\omega\) takes on values closer and closer to \(1 ?\) Note that the natural frequency of the unforced system is \(\omega_{0}=1\)

Find the general solution of the given differential equation. $$ y^{\prime \prime}-2 y^{\prime}-2 y=0 $$

Use the method of reduction of order to find a second solution of the given differential equation. \(x^{2} y^{\prime \prime}-(x-0.1875) y=0, \quad x>0 ; \quad y_{1}(x)=x^{1 / 4} e^{2 \sqrt{x}}\)

The differential equation $$ y^{\prime \prime}+\delta\left(x y^{\prime}+y\right)=0 $$ arises in the study of the turbulent flow of a uniform stream past a circular rylinder. Verify that \(y_{1}(x)=\exp \left(-\delta x^{2} / 2\right)\) is one solution and then find the general solution in the form of an integral.

A mass weighing 16 lb stretches a spring 3 in. The mass is attached to a viscous damper with a damping constant of 2 Ib-sec/ft. If the mass is set in motion from its equilibrium position with a downward velocity of 3 in / sec, find its position \(u\) at any time \(t .\) Plot \(u\) versus \(t\). Determine when the mass first returns to its equilibrium. Also find the time \(\tau\) such that \(|u(t)|<0.01\) in. fir all \(t>\tau\)
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