/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 8 Solve the given differential equ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Solve the given differential equation. $$ \frac{d y}{d x}=\frac{x^{2}}{1+y^{2}} $$

Short Answer

Expert verified
Question: Solve the given differential equation and find the implicit solution for the function 'y': $$\frac{dy}{dx} = \frac{x^2}{1 + y^2}$$ Solution: After solving the given differential equation using the separation of variables technique, we found the implicit solution as follows: $$y + \frac{y^3}{3} - \frac{x^3}{3} = C$$

Step by step solution

01

Separate the variables

Rewrite the given equation as follows: $$ \frac{dy}{dx} = \frac{x^2}{1 + y^2} $$ Now, let's separate the variables by moving the 'y' terms on one side and the 'x' terms on the other side. To do so, we simply multiply both sides by \(\(1 + y^2\)\) and \(\(dx\)\) to get: $$ (1 + y^2) dy = x^{2} dx $$
02

Integrate both sides

Integrate both sides with respect to their respective variables: $$ \int (1 + y^2) dy = \int x^{2} dx $$ The integration of the left side is quite simple, just integrate '1' and '\(\(y^2\)\)', meanwhile, integrate 'x^2' on the right side.
03

Evaluate the integrals

Left-hand side integral: $$ \int (1 + y^2) dy = y + \frac{y^3}{3} + C_1 $$ Right-hand side integral: $$ \int x^{2} dx = \frac{x^3}{3} + C_2 $$ Now, equate both sides: $$ y + \frac{y^3}{3} + C_1 = \frac{x^3}{3} + C_2 $$
04

Simplify the equation

To simplify the equation we will combine the constants and set a new constant '\(\(C\)\)' $$ y + \frac{y^3}{3} - \frac{x^3}{3} = C $$ At this point, we have obtained a solution for the given differential equation. It is an implicit solution since the function 'y' has not been explicitly solved. However, obtaining an explicit solution from this point is typically not possible, so the implicit solution is generally accepted. The final solution is: $$ y + \frac{y^3}{3} - \frac{x^3}{3} = C $$

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration Techniques
Integration is a fundamental technique used to find solutions to differential equations. When solving separable differential equations, integration enables us to handle expressions involving differentials by evaluating the antiderivative of a function. In our example, after separating the variables, we obtain two integrals that need evaluation:
  • \( \int (1 + y^2) \, dy \)
  • \( \int x^2 \, dx \)
Each integral is approached individually. For \(\int (1 + y^2) dy\), we treat "1" and "\(y^2\)" as separate functions and integrate them independently, yielding \( y + \frac{y^3}{3} \). Likewise, for \(\int x^2 \, dx \), we find the antiderivative to be \(\frac{x^3}{3}\).
Integration requires adding a constant of integration, \(C\), to account for indefinite integrals which represent families of functions. In practice, integration techniques are crucial because they transform the problem of solving differential equations into a more accessible form by evaluating key parts of the equations.
Separation of Variables
Separation of variables is a technique used to solve differential equations by separating the variables (i.e., dependent and independent variables) onto different sides of the equation. This technique is particularly useful for separable differential equations where the expression can be manipulated into a form \(N(y)\,dy = M(x)\,dx\).
In the given exercise, we first rewrote the equation \(\frac{dy}{dx} = \frac{x^2}{1 + y^2}\) in a separated form \((1 + y^2) \, dy = x^2 \, dx\). By adjusting the equation in such a way, each side contains only one variable and its differential.
This clear separation allows us to integrate each side easily with respect to its variable, leading directly to the solution without the variables being mixed. The goal is to manipulate the equation so that it can be integrated comfortably. This method is highly valued because of its direct approach and simplicity in handling certain types of differential equations.
Implicit Solutions
An implicit solution is a form of the solution to a differential equation where the dependent variable is not isolated on one side of the equation. Instead, the solution involves both the dependent and independent variables mixed together within the equation.
In our solution, the implicit form \(y + \frac{y^3}{3} - \frac{x^3}{3} = C\) is derived. The presence of terms involving both \(y\) and \(x\) indicates this implicit nature. The \(C\) in the equation represents a constant of integration which becomes part of the implicit solution.
  • Implicit solutions arise when it is not feasible to solve explicitly for the dependent variable \(y\).
  • They are accepted as valid solutions, particularly for more complex differential equations.
Implicit solutions are valuable because they still describe the relationship between the variables, even if not in a straightforward, explicit form. In many cases, obtaining an explicit solution might not be possible, making implicit solutions a necessary aspect of solving differential equations.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Suppose that a rocket is launched straight up from the surface of the earth with initial velocity \(v_{0}=\sqrt{2 g R}\), where \(R\) is the radius of the earth. Neglect air resistance. (a) Find an expression for the velocity \(v\) in terms of the distance \(x\) from the surface of the earth. (b) Find the time required for the rocket to go \(240,000\) miles (the approximate distance from the earth to the moon). Assume that \(R=4000\) miles.

Involve equations of the form \(d y / d t=f(y) .\) In each problem sketch the graph of \(f(y)\) versus \(y\), determine the critical (equilibrium) points, and classify each one as asymptotically stable, unstable, or semistable (see Problem 7 ). $$ d y / d t=y^{2}\left(4-y^{2}\right), \quad-\infty

Sometimes it is possible to solve a nonlinear equation by making a change of the dependent variable that converts it into a linear equation. The most important such equation has the form $$ y^{\prime}+p(t) y=q(t) y^{n} $$ and is called a Bernoulli equation after Jakob Bernoulli. deal with equations of this type. (a) Solve Bemoulli's equation when \(n=0\); when \(n=1\). (b) Show that if \(n \neq 0,1\), then the substitution \(v=y^{1-n}\) reduces Bernoulli's equation to a linear equation. This method of solution was found by Leibniz in 1696 .

Determine whether or not each of the equations is exact. If it is exact, find the solution. $$ (2 x+4 y)+(2 x-2 y) y^{\prime}=0 $$

Find the escape velocity for a body projected upward with an initial velocity \(v_{0}\) from a point \(x_{0}=\xi R\) above the surface of the earth, where \(R\) is the radius of the earth and \(\xi\) is a constant. Neglect air resistance. Find the initial altitude from which the body must be launched in order to reduce the escape velocity to \(85 \%\) of its value at the earth's surface.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.