Chapter 5: Problem 1
In each exercise, express the solution with the aid of power series or definite integrals. $$ y^{\prime}=y\left[1-\exp \left(-x^{2}\right)\right] $$
Short Answer
Expert verified
Solution: \(y = C e^x \exp(x^2) \text{ erfi}(x)\).
Step by step solution
01
Understand the Problem
We are given a differential equation \( y' = y[1 - \exp(-x^2)] \). This is a first-order linear differential equation, and our goal is to solve it using either power series or definite integrals.
02
Rewriting using Integrating Factor Method
Since this is a linear differential equation in the form \( y' - y[1 - \exp(-x^2)] = 0 \), we can use the integrating factor method. Rewriting in standard form: \[ y' + p(x) y = 0 \] where \(p(x) = -[1 - \exp(-x^2)]\).
03
Find the Integrating Factor
The integrating factor \( \mu(x) \) is found by solving \( \mu(x) = e^{\int p(x) \, dx} \). Calculating this: \[ \mu(x) = e^{-\int(1 - \exp(-x^2)) \, dx}\] This integral can be simplified as: \(\mu(x) = e^{-\int 1 \, dx} e^{\int \exp(-x^2) \, dx}\).
04
Simplifying the Integrating Factor
The integral \( \int 1 \, dx = x \) is straightforward, but \( \int \exp(-x^2) \, dx \) typically does not have a simple closed form and is known as the Gaussian integral. Let us express \( \mu(x) \) as:\[ \mu(x) = e^{-x} \sqrt{\pi} \text{ erf}(x) + C \]where \( \text{erf}(x) \) is the error function.
05
Solving the Differential Equation
Integrating factor \( \mu(x) \) lets us multiply both sides of the original differential equation:\[ \frac{d}{dx}[y \mu(x)] = 0.\]This implies \( y \mu(x) = C \) where \( C \) is a constant. Thus, the solution by rearranging gives us:\[ y = \frac{C}{e^{-x} \sqrt{\pi} \text{erf}(x) + C}.\]
06
Express the Solution Using Known Functions
Since the error function comes from \( \int \exp(-x^2) \, dx \), we express:\[ y = C e^{x} \exp(x^2) \text{ erfi}(x) \]where \( \text{erfi}(x) \) is the imaginary error function and is used here due to the need for analytic continuation of the Gaussian integral.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
First-order Differential Equations
In mathematics, first-order differential equations involve the derivatives of a function with respect to one variable. They are called "first-order" because they involve only the first derivative and do not require any higher-order derivatives. First-order differential equations can be linear or nonlinear. Linear equations have the form:
- \( y' + p(x)y = q(x) \)
Integrating Factor
The integrating factor is a crucial concept in solving linear first-order differential equations. The main idea is to multiply the entire equation by a function called the integrating factor, transforming it into a form that is easier to solve.For a standard linear equation:
- \( y' + p(x)y = 0 \)
- \( \mu(x) = e^{\int p(x) \, dx} \)
Gaussian Integral
The Gaussian integral is a fundamental component in probability and mathematical analysis. It is concerned with the integral of the exponential function raised to the power of a negative square.Mathematically it is represented as:
- \( \int_{-\infty}^{\infty} \exp(-x^2) \, dx = \sqrt{\pi} \)
Error Function (erf)
The error function \( \text{erf}(x) \) is a special function used in probability, statistics, and differential equations. It is closely linked to the cumulative distribution function of a normal distribution.It is defined as:
- \( \text{erf}(x) = \frac{2}{\sqrt{\pi}} \int_{0}^{x} \exp(-t^2) \, dt \)