Chapter 22: Problem 7
Obtain the Fourier series over the indicated interval for the given function. Always sketch the function that is the sum of the series obtained. $$ \begin{aligned} \text { Interval, }-\pi< x < \pi ; \text { function, } f(x) &=3 \pi+2 x, &-\pi < x < 0, \\ &=\pi+2 x, & 0 < x < \pi \end{aligned} $$
Short Answer
Step by step solution
Define the Function
Determine the Fourier Coefficients
Calculate a_0
Calculate a_n
Calculate b_n
Construct the Fourier Series
Sketch the Function
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Piecewise Functions
- From \(-\pi < x < 0\), we use the equation \(f(x) = 3\pi + 2x\).
- From \(0 < x < \pi\), the function takes the form \(f(x) = \pi + 2x\).
Fourier Coefficients
- The constant term \(a_0\), which accounts for the average value of the function over one period.
- The terms \(a_n\) relating to the cosine functions, capturing even components.
- The terms \(b_n\) associated with sine functions, capturing the odd components.
- \(a_0\) is found using the integral formula \( \frac{1}{2\pi} \int_{-\pi}^{\pi} f(x) \, dx\), summarizing the average height of the function over its interval.
- \(a_n\) and \(b_n\) use integrals of the form \( \frac{1}{\pi} \int_{-\pi}^{\pi} f(x) \cos(nx) \, dx\) and \(\frac{1}{\pi} \int_{-\pi}^{\pi} f(x) \sin(nx) \, dx\) respectively, reflecting how projections relate function behavior to these trigonometric bases.
Trigonometric Integrals
- For \(a_n\) coefficients, we integrate \(f(x)\) multiplied by \(\cos(nx)\) from \(-\pi\) to \(\pi\).
- For \(b_n\) coefficients, \(f(x)\) is multiplied by \(\sin(nx)\) and integrated over the same interval.
Periodic Functions
- The given piecewise function repeats every \(2\pi\) units.
- Each period within \(-\pi < x < \pi\) reflects similar behavior in every subsequent segment (e.g., \(\pi < x < 2\pi\)).