Chapter 22: Problem 19
Obtain the Fourier series over the indicated interval for the given function. Always sketch the function. $$ \begin{aligned} \text { Interval, }-4 < x < 4 ; \text { function, } f(x) &=1, &-4 < x < 2, \\ &=0, & 2 < x < 4 . \end{aligned} $$
Short Answer
Expert verified
The Fourier series is \( f(x) = \frac{3}{4} + \sum a_n \cos\left(\frac{n\pi x}{4}\right) \) with \( b_n = 0 \).
Step by step solution
01
Define Fourier Series Components
The Fourier series of a function is given by: \[ f(x) = a_0 + \sum_{n=1}^{\infty} \left( a_n \cos\left(\frac{n\pi x}{L}\right) + b_n \sin\left(\frac{n\pi x}{L}\right) \right) \]where \( L \) is half the period of the function. For the interval \(-4 < x < 4\), \( L = 4 \).
02
Calculate the Coefficient a_0
The zero-frequency term is computed as follows:\[ a_0 = \frac{1}{2L} \int_{-L}^{L} f(x) \, dx = \frac{1}{8} \left( \int_{-4}^{2} 1 \, dx + \int_{2}^{4} 0 \, dx \right) = \frac{1}{8} \times 6 = \frac{3}{4} \].
03
Calculate the Coefficients a_n
The coefficients \( a_n \) for cosine terms are:\[ a_n = \frac{1}{L} \int_{-L}^{L} f(x) \cos\left(\frac{n\pi x}{L}\right) \, dx \]For \(-4 < x < 2\), the integration is\[ a_n = \frac{1}{4} \left( \int_{-4}^{2} \cos\left(\frac{n\pi x}{4}\right) \, dx \right) \]Solving this integration involves integrating cosine over the interval: \[ \int \cos\left(\frac{n\pi x}{4}\right) \, dx = \frac{4}{n\pi} \sin\left(\frac{n\pi x}{4}\right) \]After computing with limits, many terms vanish or simplify based on the \( n \) value. This yields expressions dependent on \( n \).
04
Calculate the Coefficients b_n
The coefficients \( b_n \) for the sine terms are:\[ b_n = \frac{1}{L} \int_{-L}^{L} f(x) \sin\left(\frac{n\pi x}{L}\right) \, dx = \frac{1}{4} \left( \int_{-4}^{2} \sin\left(\frac{n\pi x}{4}\right) \, dx \right) \]Since \( \int \sin((ax+b))dx = -\frac{1}{a} \cos((ax+b)) + C \), calculate:\[ b_n = \frac{1}{4} \left( \int_{-4}^{2} \sin\left(\frac{n\pi x}{4}\right) \, dx \right) = 0 \]This integral typically evaluates to zero for this piecewise constant function that is symmetric on interval \(-4 < x < 4\).
05
Compose the Fourier Series
Combine the coefficients to form the overall Fourier series:\[ f(x) = \frac{3}{4} + \sum_{n=1}^{\infty} a_n \cos\left(\frac{n\pi x}{4}\right) \]With calculated values \( a_n \) and \( b_n = 0 \), this series represents the periodic extension of \( f(x) \) over the entire real line.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Piecewise Functions
A piecewise function is a function that is defined by multiple sub-functions, each of which applies to a specific interval of the main function's domain. In simpler terms, it's like having a different rule for different parts of the domain. For example, consider the function given in the problem:
- For the interval \(-4 < x < 2\), the function is constantly equal to 1.
- For the interval \(2 < x < 4\), the function is constantly equal to 0.
Trigonometric Series
Trigonometric series are a series of terms that involve trigonometric functions like sine and cosine. In a Fourier series, we express a periodic function as an infinite sum of these trigonometric functions. The use of sine and cosine is particularly powerful because they form a complete orthogonal set, which allows us to represent complex periodic waveforms precisely.
Fourier series, in particular, is a type of trigonometric series used to decompose functions into basic sinusoidal (sine and cosine) components. The Fourier series is defined as:
Fourier series, in particular, is a type of trigonometric series used to decompose functions into basic sinusoidal (sine and cosine) components. The Fourier series is defined as:
- \( f(x) = a_0 + \sum_{n=1}^{\infty} \left( a_n \cos\left(\frac{n\pi x}{L}\right) + b_n \sin\left(\frac{n\pi x}{L}\right) \right) \)
- Here, \(a_0\) represents the average value of the function over one period.
- The coefficients \(a_n\) and \(b_n\) determine the contribution of each cosine and sine term, respectively.
Integral Calculus
Integral calculus is a branch of mathematics focused on the concept of integration, which is essentially the reverse process of differentiation. It involves finding a function whose derivative is given, or, in other terms, finding the area under a curve. It's particularly important in computing Fourier series coefficients.
In the context of this exercise:
In the context of this exercise:
- The \(a_0\) coefficient was calculated using definite integrals, which represent the average value of the piecewise function over the given interval.
- Similarly, the coefficients \(a_n\) and \(b_n\) are derived using integrations with cosine and sine terms over specified intervals. These integrals take into account different parts of the piecewise function.
- For example, computing the integral of a constant function or the integration of trigonometric expressions corresponds to finding specific portions of the solution.