/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Free solutions & answers for Elementary Differential Equations Chapter 16 - (Page 6) [step by step] | 91Ó°ÊÓ

91Ó°ÊÓ

Problem 27

Find the general solution and also the singular solution, if it exists. $$ 5 p^{2}+3 x p-y=0. $$

Problem 27

Solve the equation and find a particular solution that satisfies the given boundary conditions. $$ x y^{\prime \prime}=y^{\prime}+x^{5} ; \text { when } x=1, y=\frac{1}{2}, y^{\prime}=1 $$

Problem 28

Solve the equation and find a particular solution that satisfies the given boundary conditions. $$ x y^{\prime \prime}+y^{\prime}+x=0 ; \text { when } x=2, y=-1, y^{\prime}=-\frac{1}{2} $$

Problem 28

Find the general solution and also the singular solution, if it exists. $$ p^{2}+3 x p-y=0. $$

Problem 29

Find the general solution and also the singular solution, if it exists. $$ y=x p+x^{3} p^{2}. $$

Problem 30

Solve the equation and find a particular solution that satisfies the given boundary conditions. $$ y^{\prime \prime}=x\left(y^{\prime}\right)^{2} ; \text { when } x=2, y=\frac{1}{4} \pi, y^{\prime}=-\frac{1}{4} $$

Problem 31

Solve the equation and find a particular solution that satisfies the given boundary conditions. $$ y^{\prime \prime}=x\left(y^{\prime}\right)^{2} ; \text { when } x=0, y=1, y^{\prime}=\frac{1}{2} $$

Problem 32

Solve the equation and find a particular solution that satisfies the given boundary conditions. $$ y^{\prime \prime}=-e^{-2 y} ; \text { when } x=3, y=0, y^{\prime}=1 $$

Problem 33

Solve the equation and find a particular solution that satisfies the given boundary conditions. $$ y^{\prime \prime}=-e^{-2 y} ; \text { when } x=3, y=0, y^{\prime}=-1 $$

Problem 34

Solve the equation and find a particular solution that satisfies the given boundary conditions. $$ 2 y^{\prime \prime}=\sin 2 y ; \text { when } x=0, y=\pi / 2, y^{\prime}=1 $$

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