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A 6 -in. pendulum is released from rest at an angle \(\frac{1}{10}\) rad from the vertical. Using \(g=32\left(\mathrm{ft} / \mathrm{sec}^{2}\right),\) describe the motion.

Short Answer

Expert verified
The pendulum oscillates with an amplitude of \(\frac{1}{10}\) rad and an angular frequency of 8 rad/s.

Step by step solution

01

Converting Length to Feet

First, convert the length of the pendulum from inches to feet since the gravitational acceleration is given in feet per second squared. There are 12 inches in a foot, so 6 inches is \( \frac{6}{12} = 0.5 \) feet.
02

Setting Up the Equation for Simple Harmonic Motion

The motion of a small angle pendulum can be described by simple harmonic motion. The angular displacement \( \theta(t) \) is given by the equation: \[ \theta(t) = \theta_0 \cos(\omega t), \] where \( \theta_0 \) is the initial angle, and \( \omega \) is the angular frequency.
03

Calculating Angular Frequency

The angular frequency \( \omega \) is calculated using the formula: \[ \omega = \sqrt{\frac{g}{L}}. \] Substitute \( g = 32 \) ft/s^2 and \( L = 0.5 \) ft: \[ \omega = \sqrt{\frac{32}{0.5}} = \sqrt{64} = 8 \, \text{rad/s}. \]
04

Describing the Motion Using the General Solution

Substituting the known values into the motion equation: \[ \theta(t) = \frac{1}{10} \cos(8t). \] This describes a pendulum oscillating with an amplitude of \( \frac{1}{10} \) rad and an angular frequency of 8 rad/s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pendulum Dynamics
A pendulum consists of a mass, known as a bob, attached to a string or rod of a certain length. It is a classic example of simple harmonic motion (SHM), especially under the assumption of small oscillations. When the pendulum is displaced from its equilibrium or rest position, the force of gravity acts to bring it back. However, inertia causes it to overshoot this position, creating an oscillatory motion.

In SHM, the restoring force is proportional to the displacement. For a pendulum, this means that the more you displace it, the stronger the force trying to restore it back to the midpoint. This force is what allows pendulums to have predictable and periodic motion.

The key components defining this motion include:
  • The length of the pendulum: The longer the string, the slower the pendulum swings.
  • The amplitude: The maximum angle from the vertical. It affects the energy but not the rate of swing for small angles.
The dynamics of a pendulum, especially under small angles (small-angle approximation), make it a perfect candidate for illustrating simple harmonic motion.
Angular Frequency
Angular frequency is a crucial concept when it comes to understanding pendulum motion. It is denoted by the Greek letter omega (\( \omega \tag{ω}\)). It represents how fast the pendulum oscillates back and forth in radians per second.

To compute the angular frequency of a pendulum, we use the formula:

\[ \omega = \sqrt{\frac{g}{L}} \]Here:
  • \(g\tag{g}\) is the gravitational acceleration,
  • \(L\tag{L}\) is the length of the pendulum.
High angular frequency means the pendulum completes its swings quickly, while low angular frequency means it swings more slowly. By substituting the values from our exercise, we derived the angular frequency as 8 rad/s, indicating that the pendulum makes 8 full-back and forth movements every second.
Gravitational Acceleration
Gravitational acceleration, usually denoted as \(g\tag{g}\), is an essential factor influencing pendulum dynamics. It is the acceleration due to Earth's gravitational pull, and its standard value is approximately 9.81 m/s² or 32 ft/s², depending on the measurement units. In the context of pendulum motion, gravitational acceleration determines how fast the pendulum speeds up as it swings closer to the vertical position.

Gravitational acceleration's role in a pendulum's motion is critical, especially with the formula for calculating angular frequency:\[ \omega = \sqrt{\frac{g}{L}} \]This formula shows that gravitational acceleration directly affects how quickly a pendulum can complete an oscillation. A greater value for \(g\tag{g}\) results in a quicker swing, while a smaller value results in a slower swing. Thus, understanding gravitational acceleration helps in grasping why pendulums behave differently under varying conditions.

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Most popular questions from this chapter

An object weighing \(w\) lb is dropped from a height \(h\) ft above the earth. At time \(t(\sec )\) after the object is dropped, let its distance from the starting point be \(x\) (ft), measured positive downward. Assuming air resistance to be negligible, show that \(x\) must satisfy the equation $$\frac{w}{g} \frac{d^{2} x}{d t^{2}}=w$$ as long as \(x

A spring is stretched 1.5 in. by a 4 -lb weight. Let the weight be pulled down 3 in. below equilibrium and released. If there is an impressed force \(8 \sin 16\) acting upon the spring, describe the motion.

A certain straight-line motion is determined by the differential equation $$\frac{d^{2} x}{d t^{2}}+2 \gamma \frac{d x}{d t}+169 x=0$$ and the conditions that when \(t=0, x=0,\) and \(v=8 \mathrm{ft} / \mathrm{sec} .\) (a) Find the value of \(\gamma\) that leads to critical damping, determine \(x\) in terms of \(t,\) and draw a graph for \(0 \leq t \leq 0.2\). (b) Use \(\gamma=12\). Find \(x\) in terms of \(t\) and draw the graph. (c) Use \(\gamma=14\). Find \(x\) in terms of \(t\) and draw the graph.

A spring is such that a \(4-1 \mathrm{~b}\) weight stretches it 6 in. The 4 -lb weight is attached to the vertical spring and reaches its equilibrium point. The weight is then \((t=0)\) drawn downward 3 in. and released. There is a simple harmonic exterior force equal to \(\sin 8 t\) impressed upon the whole system. Find the time for each of the first four stops following \(t=0 .\) Put the stops in chronological order.

A 20-lb weight stretches a certain spring 10 in. Let the spring first be compressed 4 in., and then the 20 -lb weight attached and given an initial downward velocity of \(8 \mathrm{ft} / \mathrm{sec} .\) Find how far the weight would drop.

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