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Determine in each exercise whether or not the function is homogeneous. If it is homogeneous, state the degree of the function. $$ 2 y+\sqrt{x^{2}+y^{2}} $$

Short Answer

Expert verified
The function is homogeneous of degree 1.

Step by step solution

01

Define Homogeneous Functions

A function \( f(x, y) \) is said to be homogeneous of degree \( n \) if, for any scalar \( t \), \( f(tx, ty) = t^n f(x, y) \). This definition will help us check the given function for homogeneity.
02

Substitute and Simplify

Substitute \( x = tx \) and \( y = ty \) into the function: \[ f(tx, ty) = 2ty + \sqrt{(tx)^2 + (ty)^2} \] \[ = 2ty + \sqrt{t^2x^2 + t^2y^2} \] This simplifies to: \[ = 2ty + t\sqrt{x^2 + y^2} \]
03

Check Homogeneity Condition

Compare the expression obtained in Step 2 with \( t^n f(x, y) \). The original function is \( 2y + \sqrt{x^2 + y^2} \) and for it to be homogeneous of degree \( n \), we should have: \[ f(tx, ty) = t^n(2y + \sqrt{x^2 + y^2}) \] This implies: \[ 2ty + t\sqrt{x^2 + y^2} = t^n(2y + \sqrt{x^2 + y^2}) \]
04

Analyze the Condition

The requirement is that \( 2ty + t\sqrt{x^2 + y^2} \) should be equal to \( t^n(2y + \sqrt{x^2 + y^2}) \) for some degree \( n \). Separately, this implies:1. \( 2ty = t^n \times 2y \)2. \( t\sqrt{x^2 + y^2} = t^n \times \sqrt{x^2 + y^2} \)For both conditions to hold for all \( x \), \( y \), and \( t \) (including \( y=0 \)), \( n \) must be 1 for the first term and 1 for the second term consistently.
05

Conclude

Since for both terms, \( n = 1 \), the function is homogeneous of degree 1.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degree of a Function
In the realm of mathematics, understanding the degree of a function is essential when dealing with homogeneous functions. A function's degree, particularly in homogeneous functions, provides invaluable insights into its scaling properties. To determine the degree, observe how a function transforms under the scaling of its input variables. Let's denote a function as \( f(x, y) \). If we replace \( x \) and \( y \) with \( tx \) and \( ty \) \( (t \) being a scalar, meaning just a number), and the function then behaves like \( t^n f(x, y) \), we say the function is homogeneous of degree \( n \).

In practical examples, consider a function such as \( 2y + \sqrt{x^2 + y^2} \). Through substitution and simplification, it can be checked for homogeneity: transform inputs \( x \) and \( y \) to \( tx \) and \( ty \). See if you can factor out a common scalar (or number) \( t^n \) across the entire function. If so, \( n \) is your degree of homogeneity. For instance, with our example, a thorough breakdown shows it indeed scales perfectly with \( n=1 \). This intuitive understanding aids in recognizing how functions stretch or compress when their inputs are uniformly scaled.
Homogeneity Check
Conducting a homogeneity check involves a series of steps that help us determine if a function is homogeneous and what its degree might be. Start by substituting the variables of your function with their scaled counterparts. For example, replace \( x \) with \( tx \) and \( y \) with \( ty \).

After substitution, simplify the resulting expression. With our example, transforming \( (x, y) \) to \( (tx, ty) \) changes the function to \( 2ty + \sqrt{t^2x^2 + t^2y^2} \). Simplifying this yields \( 2ty + t\sqrt{x^2 + y^2} \).

Now, for a homogeneity check, compare this simplified expression with \( t^n f(x, y) \), where \( f(x, y) = 2y + \sqrt{x^2 + y^2} \). If you can equate \( 2ty + t\sqrt{x^2 + y^2} \) to \( t^n(2y + \sqrt{x^2 + y^2}) \) and find a consistent \( n \), your function is homogeneous. Each term must show that \( t^n \) holds for all input variable values, confirming the degree \( n \) and the homogeneity of the function.
Scalar Multiplication
Scalar multiplication is a fundamental concept that helps place homogeneous functions into a broader context. It's a straightforward idea where a scalar (a single number) multiplies variables within a function. This multiplication directly affects their magnitudes but not their directions, simplifying the task of evaluating functions for homogeneity.

For instance, consider a simple rescaling of the function by a scalar \( t \): \( x \to tx \) and \( y \to ty \). Each term of the function is multiplied by \( t \), and through this action, each segment of the function's expression scales uniformly. This is precisely how the function \( 2y + \sqrt{x^2 + y^2} \) transforms when inputs are rescaled, making it vital when conducting homogeneity checks.

To recap, scalar multiplication in homogeneous functions is a tool confirming how the entire function scales. It's through such scalar adjustments that we can check scaling properties to confirm whether a function maintains its form and determine its degree of homogeneity.

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