Chapter 13: Problem 15
We consider the general homogeneous system with real coefficients $$ \left(\begin{array}{l} x \\ y \end{array}\right)^{\prime}=\left(\begin{array}{ll} a & b \\ c & d \end{array}\right)\left(\begin{array}{l} x \\ y \end{array}\right) $$ Find the value of the Wronskian in the complex case for \(t=0\) and show that it is not zero.
Short Answer
Step by step solution
Define the System
Find Eigenvalues
Construct General Solution
Compute the Wronskian
Evaluate the Wronskian at \( t = 0 \)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Wronskian
- If the Wronskian is non-zero at a point, then the solutions are linearly independent at that point.
- In our context, since the Wronskian evaluated at \( t = 0 \) is \( \det(\mathbf{v_1}, \mathbf{v_2}) \), and given \( \mathbf{v_1} \) and \( \mathbf{v_2} \) are linearly independent, \( W(0) \) is non-zero.
eigenvalues and eigenvectors
- For a 2x2 system, this becomes \( (a-\lambda)(d-\lambda) - bc = 0 \), where \( a, b, c, \) and \( d \) are entries from the matrix.
- The solutions to this equation are the eigenvalues, which we call \( \lambda_1 \) and \( \lambda_2 \).
linear independence
- In our exercise, the vectors \( \mathbf{v_1} \) and \( \mathbf{v_2} \) are demonstrated to be linearly independent by the non-zero value of their determinant.
- Linear independence in the context of differential equations ensures that each solution brings unique information that can span the solution space completely.