Chapter 12: Problem 11
Express \(F(t)\) in terms of the \(\alpha\) function and find \(L\\{F(t)\\}\).
$$
\begin{aligned}
F(t) &=t^{2}, & & 0
Short Answer
Expert verified
\( L\{F(t)\} = \frac{2}{s^3} - \frac{2e^{-s}}{s^3} + \frac{3e^{-s}}{s} - \frac{3e^{-2s}}{s} \).
Step by step solution
01
Define the Alpha Function
The alpha function, commonly represented using the Heaviside step function, is denoted as \( u(t-c) \) where \( c \) is a constant. The function is defined as 0 for \( t<c \) and 1 for \( t \geq c \). It helps in expressing piecewise functions like \( F(t) \) in a single equation.
02
Express the Piecewise Function Using Heaviside Functions
The given piecewise function \( F(t) \) is:\[F(t) = \begin{cases} t^2, & 0 < t < 1 \ 3, & 1 \leq t < 2 \ 0, & t \geq 2\end{cases}\]Using the Heaviside function, express \( F(t) \) as:\[ F(t) = t^2 u(t) - t^2 u(t-1) + 3u(t-1) - 3u(t-2) \]
03
Calculate the Laplace Transform of Each Term
To find \( L\{F(t)\} \), calculate the Laplace Transform of each term:- For \( t^2 u(t) \): \[ L\{t^2\} = \frac{2}{s^3} \]- For \( -t^2 u(t-1) \): Apply the shifting property: \[ L\{-t^2 u(t-1)\} = -e^{-s} L\{t^2\} = -e^{-s} \frac{2}{s^3} \]- For \( 3u(t-1) \): Apply the shifting property: \[ L\{3u(t-1)\} = 3e^{-s} \frac{1}{s} = \frac{3e^{-s}}{s} \]- For \( -3u(t-2) \): \[ L\{-3u(t-2)\} = -3e^{-2s} \frac{1}{s} = -\frac{3e^{-2s}}{s} \]
04
Combine the Laplace Transforms
Add the Laplace Transforms found in Step 3:\[ L\{F(t)\} = \frac{2}{s^3} - \frac{2e^{-s}}{s^3} + \frac{3e^{-s}}{s} - \frac{3e^{-2s}}{s} \]This expression represents the Laplace transform of the entire function \( F(t) \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Heaviside function
The Heaviside function, also known as the unit step function, is a fundamental tool in mathematics, especially in control systems and signal processing. It is a piecewise function represented as \( u(t-c) \), where \( c \) is a constant:
In the given exercise, the Heaviside function facilitates the expression of \( F(t) \) in a single equation. It minimizes complexity by using mathematical operations on these step functions to handle changes over different ranges of \( t \). This leads to expressions like \( t^2 u(t) - t^2 u(t-1) + 3u(t-1) - 3u(t-2) \), combining several conditions of the original piecewise function into a unified form.
- For \( t < c \), \( u(t-c) = 0 \).
- For \( t \geq c \), \( u(t-c) = 1 \).
In the given exercise, the Heaviside function facilitates the expression of \( F(t) \) in a single equation. It minimizes complexity by using mathematical operations on these step functions to handle changes over different ranges of \( t \). This leads to expressions like \( t^2 u(t) - t^2 u(t-1) + 3u(t-1) - 3u(t-2) \), combining several conditions of the original piecewise function into a unified form.
piecewise function
A piecewise function is a type of function that is defined by multiple sub-functions, each of which applies to a certain interval of the main function's domain. These types of functions are used when a function behaves differently across various periods, ranges, or conditions.
Structuring a piecewise function can be thought of as building varied "pieces" of a puzzle that, when put together, give a complete picture of how the function behaves.
For example, in the given problem, \( F(t) \) is defined as:
Structuring a piecewise function can be thought of as building varied "pieces" of a puzzle that, when put together, give a complete picture of how the function behaves.
For example, in the given problem, \( F(t) \) is defined as:
- \( t^2 \) for \( 0 < t < 1 \)
- 3 for \( 1 < t < 2 \)
- 0 for \( t > 2 \)
Laplace transform properties
The Laplace transform is a powerful mathematical tool widely used for analyzing linear time-invariant systems. It transforms a function of time \( t \) into a function of a complex variable \( s \), turning differential equations into algebraic equations, which are easier to manipulate.
To solve for the Laplace transform of complex functions, several key properties come in handy:
To solve for the Laplace transform of complex functions, several key properties come in handy:
- Linearity: If \( F(t) = a f(t) + b g(t) \), then \( L\{F(t)\} = a L\{f(t)\} + b L\{g(t)\} \).
- Shifting: For a function \( f(t-a)u(t-a) \), the Laplace transform is \( e^{-as}L\{f(t)\} \).
- Piecewise Nature: Handling piecewise functions using Heaviside involves calculating the transform segment-wise and then combining the results.
- The transformation of \( t^2 u(t) \) results in \( \frac{2}{s^3} \).
- The shifting property is applied to terms like \( -t^2 u(t-1) \), which transforms to \( -e^{-s} \frac{2}{s^3} \).
- The other terms, such as \( 3u(t-1) \) and \( -3u(t-2) \), utilize similar principles to shift and scale accordingly.