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Differentiate the following functions. $$ u=\sec ^{2} x $$

Short Answer

Expert verified
Answer: The derivative of the function \(u = \sec^2(x)\) with respect to x is \(\frac{du}{dx} = \frac{2\cos(x)\sin(x)}{(\cos^{2}(x))^2}\).

Step by step solution

01

Rewrite the function using powers and cosines

We will rewrite the secant in terms of cosines to make it easier to differentiate. Remember, sec(x) is defined as the inverse of cos(x). So our function becomes: $$ u = \frac{1}{(\cos^2(x))} $$
02

Use the chain rule

Now we will use the chain rule to differentiate the given function. The chain rule states that: $$ \frac{du}{dx} = \frac{du}{dv} \cdot \frac{dv}{dx} $$ Let's define v = cos^2(x). So, the given function u can be rewritten as: $$ u = \frac{1}{v} $$ We will first find the derivative of u with respect to v: $$ \frac{du}{dv} = -\frac{1}{v^2} $$ Now, we will find the derivative of v with respect to x: $$ v = \cos^2(x) $$ $$ \frac{dv}{dx} = 2\cos(x)(-\sin(x)) = -2\cos(x)\sin(x) $$
03

Multiply du/dv and dv/dx to get the final derivative

Now, we have found both \(\frac{du}{dv}\) and \(\frac{dv}{dx}\). To find the derivative of u with respect to x, we need to multiply them: $$ \frac{du}{dx} = \frac{du}{dv} \cdot \frac{dv}{dx} $$ So, we get: $$ \frac{du}{dx} = -\frac{1}{v^2} \cdot (-2\cos(x)\sin(x)) $$ Now, substitute the value of v (v = cos^2(x)) back into the equation: $$ \frac{du}{dx} = -\frac{1}{(\cos^{2}(x))^2} \cdot (-2\cos(x)\sin(x)) $$
04

Simplify the expression

Now we can simplify the expression to get our final answer for the derivative of u with respect to x: $$ \frac{du}{dx} = \frac{2\cos(x)\sin(x)}{(\cos^{2}(x))^2} $$ Therefore, the derivative of the given function is: $$ \frac{du}{dx} = \frac{2\cos(x)\sin(x)}{(\cos^{2}(x))^2} $$

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Chain Rule
Differentiating a composite function is a bit different from regular differentiation. This is where the chain rule comes in handy. The chain rule is a technique for differentiating compositions of functions.

Think of it as a rule that helps you "chain" together derivatives. When you have a function inside another function, you can differentiate it by finding the derivative of the outside function and then multiplying it by the derivative of the inside function. This is the mathematical representation:
  • If you have a composite function, say \( y = f(g(x)) \)
  • The derivative \( \frac{dy}{dx} \) is found by multiplying \( \frac{dy}{dg} \) and \( \frac{dg}{dx} \).
In the exercise, the function \( u \) was rewritten in terms of another function \( v \) to make differentiation easier. Using the chain rule meant differentiating \( u \) with respect to \( v \), and \( v \) with respect to \( x \). The result was the product of these two derivatives.
Trigonometric Functions in Differentiation
Trigonometric functions often show up in calculus problems. They have their own set of derivative rules that are crucial to remember.

In this problem, the function involved secant, specifically \( u = \sec^2(x) \). For differentiation, we needed to convert it into the cosine form, since secant is the reciprocal of cosine.
  • Secant is defined as \( \sec(x) = \frac{1}{\cos(x)} \).
  • That makes \( \sec^2(x) = \frac{1}{\cos^2(x)} \).
For this exercise, turning \( \sec^2(x) \) into a more familiar form like \( \cos(x) \) helped apply the chain rule effectively.

The key takeaway is that trigonometric identities and relationships are essential in transforming complex expressions into simpler forms for differentiation.
Key Calculus Techniques: Simplifying and Rewriting
A core part of solving calculus problems efficiently is knowing how to simplify and rewrite expressions. This often involves algebraic manipulations and using identities to make derivatives easier to compute.

In our example with \( u = \sec^2(x) \), simplification was achieved by rewriting secant in terms of cosine. This made the function recognizable and workable for direct differentiation.
  • Convert functions to trigonometric identities if possible.
  • Use algebra to rewrite in simpler forms.
  • Make use of chain rule, product rule, and quotient rule as needed.
These techniques allow us to tackle complex functions and make the process of differentiation straightforward. Remember, differentiation isn't just about memorizing formulas—it's also about understanding how to manipulate and break down expressions to find the derivative more easily.

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