/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 Simplify each expression. All va... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Simplify each expression. All variables represent positive real numbers. See Example 7. $$ 8^{-1 / 3} $$

Short Answer

Expert verified
The expression simplifies to \(\frac{1}{2}\).

Step by step solution

01

Understand the Meaning of the Expression

We are given the expression \(8^{-1/3}\). This is represented as a power expression where 8 is the base, and \(-1/3\) is the exponent.
02

Apply Negative Exponent Rule

A negative exponent indicates that we can take the reciprocal of the base. Thus, \(8^{-1/3} = \frac{1}{8^{1/3}}\). Now, we need to focus on calculating \(8^{1/3}\).
03

Evaluate the Cube Root

The expression \(8^{1/3}\) implies finding the cube root of 8. Since \(2^3 = 8\), \(8^{1/3} = 2\).
04

Simplify the Expression

Replace \(8^{1/3}\) with 2 in the reciprocal expression. Thus, \(\frac{1}{8^{1/3}} = \frac{1}{2}\).
05

Final Answer

The simplified expression of \(8^{-1/3}\) is \(\frac{1}{2}\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Negative Exponents
In mathematics, a negative exponent is a way to signify the reciprocal of a positive exponent. When you see an expression like \(8^{-1/3}\), the negative exponent means that you first take the reciprocal of the base number raised to the positive version of that exponent.

Here's a step-by-step look at how to handle negative exponents:
  • Identify the base and the negative exponent. For example, in \(8^{-1/3}\), 8 is the base, and \(-1/3\) is the exponent.
  • Convert the expression to its reciprocal by changing the negative exponent into a positive. Use the formula: \(a^{-m} = \frac{1}{a^m}\). So, \(8^{-1/3}\) becomes \(\frac{1}{8^{1/3}}\).
This conversion simplifies the problem, allowing you to focus on solving the expression with a positive exponent.
Cube Roots
Cube roots are the opposite operation of cubing a number. To cube a number means to multiply it by itself twice, whereas a cube root aims to find a number that, when cubed, gives the original number. For example, when dealing with \(8^{1/3}\):

To find the cube root of a number:
  • Identify the number you need the cube root of, which is the base in our expression \(8^{1/3}\).
  • Think of the number that when multiplied by itself three times yields the base number. So, since \(2 \times 2 \times 2 = 8\), \(2^3 = 8\), this means the cube root of 8 is 2.
Cube roots are helpful in simplifying expressions involving fractional exponents. Recognizing this relationship speeds up calculation and simplification.
Reciprocals
Understanding reciprocals is crucial when working with expressions involving inverse operations. A reciprocal of a number is essentially 1 divided by that number. For example, the reciprocal of 2 is \(\frac{1}{2}\).

When you encounter a negative exponent like in \(8^{-1/3}\), the concept of reciprocals helps transform the expression:
  • The negative exponent \(-1/3\) initially suggests that 8 should be handled as a reciprocal, resulting in \(\frac{1}{8^{1/3}}\).
  • Once you evaluate the cube root of 8 to find it equals 2, you replace and simplify the expression to \(\frac{1}{2}\).
Reciprocals simplify expressions and allow us to handle negative exponents intuitively by flipping the fractions.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.