Chapter 9: Problem 29
Multiply and simplify. All variables represent positive real numbers. $$ \sqrt{2}(4 \sqrt{6}+2 \sqrt{7}) $$
Short Answer
Expert verified
The simplified expression is \( 8\sqrt{3} + 2\sqrt{14} \).
Step by step solution
01
Distribute the Square Root
To solve this exercise, begin by distributing the factor \( \sqrt{2} \) to each term inside the parenthesis \( (4\sqrt{6} + 2\sqrt{7}) \). This means you will multiply \( \sqrt{2} \) with \( 4\sqrt{6} \) and \( 2\sqrt{7} \) separately.
02
Multiply the First Terms
Multiply \( \sqrt{2} \) with the first term \( 4\sqrt{6} \):\[ \sqrt{2} \times 4\sqrt{6} = 4(\sqrt{2} \times \sqrt{6}) \].Using the property of radicals that \( \sqrt{a} \times \sqrt{b} = \sqrt{ab} \), you get: \[ 4 \sqrt{12} \].
03
Simplify \( \sqrt{12} \)
Simplify \( \sqrt{12} \) by identifying perfect squares: \[ \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3} \].Thus, \( 4 \sqrt{12} = 4 \times 2\sqrt{3} = 8\sqrt{3} \).
04
Multiply the Second Terms
Multiply \( \sqrt{2} \) with the second term \( 2\sqrt{7} \): \[ \sqrt{2} \times 2\sqrt{7} = 2(\sqrt{2} \times \sqrt{7}) = 2\sqrt{14} \].
05
Combine the Results
Combine the results from the multiplication to get the final expression:\[ 8\sqrt{3} + 2\sqrt{14} \].Since \( \sqrt{3} \) and \( \sqrt{14} \) are different, you cannot simplify further.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Radicals
Radicals are mathematical symbols used to represent the root of a number. The most common radical is the square root, denoted by the symbol \( \sqrt{} \). When you see this symbol, it means you're looking for a number which, when multiplied by itself, gives the original number under the radical.
For example, the square root of 9 is 3, because \( 3 \times 3 = 9 \).
For example, the square root of 9 is 3, because \( 3 \times 3 = 9 \).
- Radicals can apply to other roots, not just square roots, like cube roots (\( \sqrt[3]{} \)).
- The radicand is the number under the radical symbol. In \( \sqrt{6} \), the number 6 is the radicand.
- Radicals have special rules: \( \sqrt{a \times b} = \sqrt{a} \times \sqrt{b} \).
Simplifying Expressions
Simplifying expressions involving radicals can often make them easier to understand and work with.
Here’s how you go about simplifying:
Here’s how you go about simplifying:
- Look for Perfect Squares: Check if there are any squares in the radicand. For \( \sqrt{12} \), notice that 12 can be expressed as \( 4 \times 3 \) where 4 is a perfect square.
- Break Down the Expression: Use the property \( \sqrt{a \times b} = \sqrt{a} \times \sqrt{b} \). For \( \sqrt{12} \), it becomes \( \sqrt{4} \times \sqrt{3} = 2\sqrt{3} \).
- Multiply Coefficients: Once simplified, multiply any coefficients outside the radicals together. If you have 4 in front of \( \sqrt{12} \), then simplify it to become \( 8\sqrt{3} \).
The Distributive Property with Radicals
The distributive property is a fundamental rule in algebra that lets you multiply a single term by each term inside a parenthesis.
This is crucial when dealing with expressions that contain sums or differences inside a parenthesis.
This is crucial when dealing with expressions that contain sums or differences inside a parenthesis.
- This property is written as \( a(b + c) = ab + ac \).
- When you have radicals, apply this by multiplying outside numbers with each term inside the parenthesis. For example, \( \sqrt{2}(4\sqrt{6} + 2\sqrt{7}) \).
- By distributing \( \sqrt{2} \), it gets multiplied with each term: \( \sqrt{2} \times 4\sqrt{6} \) and \( \sqrt{2} \times 2\sqrt{7} \).
- This distribution helps to break down complex expressions into simpler parts, making them easier to handle.