Chapter 8: Problem 92
Solve each equation and inequality. For the inequalities, graph the solution set and write it using interval notation. \(-|3 x+1|<-8\)
Short Answer
Expert verified
The solution is \((-\infty, -3) \cup \left(\frac{7}{3}, \infty\right)\).
Step by step solution
01
Understanding the Absolute Value Inequality
The given inequality is \(-|3x+1| < -8\). This inequality involves an absolute value and a comparison to a negative number. We need to isolate the absolute value first.
02
Analyzing the Expression
Given \(-|3x+1| < -8\), let's multiply every term by -1 to reverse the inequality sign. This gives:\(|3x+1| > 8\). The inequality reverses because multiplying by a negative number flips the inequality sign.
03
Breaking Down the Absolute Value Inequality
Absolute value inequality \(|3x+1| > 8\) transforms into two separate inequalities: 1. \(3x + 1 > 8\)2. \(3x + 1 < -8\)
04
Solving the First Inequality
For the inequality \(3x + 1 > 8\):Subtract 1 from both sides: \(3x > 7\). Divide each side by 3 to solve for \(x\):\(x > \frac{7}{3}\).
05
Solving the Second Inequality
For the inequality \(3x + 1 < -8\):Subtract 1 from both sides: \(3x < -9\).Divide each side by 3 to solve for \(x\):\(x < -3\).
06
Combining and Graphing Solutions
Combine the solutions: \(x > \frac{7}{3}\) OR \(x < -3\). On a number line:Identify the regions where these inequalities are true. The solution is all values of \(x\) greater than \(\frac{7}{3}\) or less than \(-3\). This forms two disjoint intervals.
07
Interval Notation
Write the solution in interval notation:The solution is \( (-\infty, -3) \cup \left(\frac{7}{3}, \infty\right) \). These intervals connote the sets of \(x\) that satisfy the original inequality.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Interval Notation
Interval notation is a concise way of expressing ranges of numbers that are solutions to inequalities. It simplifies complex descriptions of numbers into compact forms. For example, if we talk about numbers less than -3, we describe this set as \((-\infty, -3)\). Similarly, numbers greater than \(\frac{7}{3}\) are written as \(\left(\frac{7}{3}, \infty\right)\). This notation uses brackets and parentheses to denote whether endpoints are included or excluded.
- Round parentheses, \(()\), mean that the endpoint is not included in the interval. For instance, \((-\infty, -3)\) means \(x\) values are less than -3.
- Square brackets, \([]\), mean the endpoint is included. For example, \([2, 5]\) includes every number from 2 to 5, including both 2 and 5 themselves.
Graphing Inequalities
When we graph inequalities like \(x > \frac{7}{3}\) or \(x < -3\), we use a number line for a clear visual representation. It helps us see which areas satisfy the inequality conditions. Here's how to graph them:
- Plot empty circles at \(-3\) and \(\frac{7}{3}\), indicating these points are not part of the solution. An empty circle means the endpoint is not included, aligning with our interval notation.
- Shade the region to the left of \(-3\) and the right of \(\frac{7}{3}\). This shading signifies that all numbers in these areas satisfy the inequalities.
Solving Inequalities
Solving inequalities follows a series of steps similar to solving equations, but with some key differences, especially when dealing with absolute values and negative signs. When we have an absolute value inequality like \(|3x + 1| > 8\), we need to solve it in two parts. Here's how we solve them:
- Break down the absolute value inequality into two separate inequalities: \(3x + 1 > 8\) and \(3x + 1 < -8\). This distinction arises because the absolute value represents both positive and negative scenarios.
- Solve each inequality independently. For \(3x + 1 > 8\), subtract 1 from both sides to get \(3x > 7\), then divide by 3 to find \(x > \frac{7}{3}\).
- For \(3x + 1 < -8\), subtract 1 from both sides to get \(3x < -9\), then divide by 3 to find \(x < -3\).