Chapter 8: Problem 77
Solve the inequality in part a. Graph the solution set and write it in interval notation. Then use your work from part a to determine the solution set for the compound inequality in part b. (No new work is necessary!) Graph the solution set and write it in interval notation. a. \(3 x-2 \geq 4\) and \(x+6 \geq 12\) b. \(3 x-2 \geq 4\) or \(x+6 \geq 12\)
Short Answer
Step by step solution
Solve First Inequality
Solve Second Inequality
Combine Solutions for Part A
Graph the Solution for Part A
Write Solution in Interval Notation for Part A
Determine Solution for Part B
Graph the Solution for Part B
Write Solution in Interval Notation for Part B
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Interval Notation
- \(x \geq 6\),
- this means all numbers starting from 6 to infinity meet the condition.
- \([6, \infty)\), where "\([\)" indicates that 6 is included.
It's essential to always follow these specific signs, as they determine if numbers on the boundary are included or beyond your interval.
Exploring Compound Inequalities
- \(3x - 2 \geq 4\) (which simplifies to \(x \geq 2\))
- and \(x + 6 \geq 12\) (simplifying to \(x \geq 6\)).
- The overlap, or most restrictive solution, is the solution for both, being \(x \geq 6\).
- Either \(x \geq 2\)
- or \(x \geq 6\) will suffice.
Using Graphical Solutions
To graph an inequality like \(x \geq 6\), begin by drawing a number line and placing a closed circle over the number 6.
This closed circle indicates that 6 is included in the solution set. Then, shade the entire region to the right of 6 to represent all numbers greater than or equal to 6.
- The shaded area forms your graphical solution.
This shading clearly displays any number greater than or equal to 2 fulfills the inequality, encompassing all solutions from the key initial problems we explored.
These graphs are not only proof of the solution but also a handy check to ensure all possibilities are considered in compound inequalities.