/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 71 Let \(f(x)=|x+3| .\) For what va... [FREE SOLUTION] | 91Ó°ÊÓ

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Let \(f(x)=|x+3| .\) For what value(s) of \(x\) is \(f(x)=3 ?\)

Short Answer

Expert verified
The solutions are \(x = 0\) and \(x = -6\).

Step by step solution

01

Understanding Absolute Value Function

The function given is \(f(x) = |x+3|\). This function represents the absolute value, which means it outputs the non-negative value of the expression inside the absolute value bars \(x + 3\). Our goal is to find the values of \(x\) such that \(f(x) = 3\).
02

Setting Up the Equation

To solve for \(x\) when \(f(x) = 3\), we set \(|x+3| = 3\). This equation means that the distance from \(x + 3\) to 0 must be 3.
03

Solving the Absolute Value Equation

An absolute value equation \(|A| = B\) can be rewritten as two linear equations: \(A = B\) and \(A = -B\). Here, \(|x+3| = 3\) gives us two equations: \(x+3 = 3\) and \(x+3 = -3\).
04

Solving Linear Equations

Solve the first equation: \(x + 3 = 3\).1. Subtract 3 from both sides: \(x = 0\).Solve the second equation: \(x + 3 = -3\).1. Subtract 3 from both sides: \(x = -6\).
05

Verifying the Solutions

Check the solutions by plugging them back into the original function:1. If \(x = 0\), then \(f(0) = |0 + 3| = 3\).2. If \(x = -6\), then \(f(-6) = |-6 + 3| = 3\).Both solutions satisfy the equation \(f(x) = 3\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Solving Linear Equations
Solving linear equations form the basis of solving all kinds of equations in algebra. In the context of an absolute value equation like \(|x+3| = 3\), solving linear equations involves breaking down the absolute value into two possible straightforward scenarios:
  • The expression inside the absolute value equals the number, giving us \(x + 3 = 3\).
  • The expression inside the absolute value equals the negative of the number, giving us \(x + 3 = -3\).
The next steps are simple subtraction:
  • For \(x + 3 = 3\), subtract 3 from both sides and you'll find \(x = 0\).
  • For \(x + 3 = -3\), subtract 3 from both sides and you get \(x = -6\).
This process helps to isolate the variable \(x\) and find the values that satisfy the original equation. Practice with simple calculations like this can strengthen your skills in algebra and provide a solid foundation for solving more complex equations.
Functions in Algebra
In algebra, a function like \(f(x) = |x+3|\) is a rule that assigns to each element \(x\) a specific value. For absolute value functions, this involves evaluating the expression inside the absolute value brackets and then taking its non-negative value.
Consider an input, such as \(x = 0\):
  • The function outputs \(|0 + 3| = 3\).
Each specific value of \(x\) will have a corresponding \(f(x)\) value, showing how functions map inputs to outputs systematically. Understanding how to evaluate a function with specific inputs is crucial as it paves the way to understand more complex functions that appear everywhere in mathematics and science.
Distance in Absolute Value
The absolute value, represented by \(|A|\), is essentially the distance of a number or expression \(A\) from 0 on the number line. It is always non-negative, as distance itself can't be negative.
In the context of the function \(f(x) = |x+3|\), setting the function equal to 3, i.e., \(f(x) = 3\), indicates we are seeking values of \(x\) that are exactly a distance of 3 units away from 0 along the number line, whether to the left or right.
This concept of distance helps to visually understand why two solutions arise from an absolute value equation: one on each side of the center point of the expression \(x + 3\). Teaching students to visualize equations in this way enhances comprehension and gives greater insight into how mathematical functions behave.

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Most popular questions from this chapter

Wood Production. The total world wood production can be modeled by a linear function. In \(1960,\) approximately \(2,400\) million cubic feet of wood were produced. since then, the amount of increase has been approximately 25.5 million cubic feet per year. (Source: Earth Policy Institute) a. Let \(t\) be the number of years after 1960 and \(W\) be the number of million cubic feet of wood produced. Write a linear function \(W(t)\) to model the production of wood. b. Use your answer to part a to estimate how many million cubic feet of wood the world produced in 2010 .

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