Chapter 8: Problem 68
Solve each inequality. Graph the solution set and write it using interval notation. \(0 \leq|6 x-3|-5\)
Short Answer
Expert verified
The solution in interval notation is \((-\infty, -\frac{1}{3}] \cup [\frac{4}{3}, \infty)\).
Step by step solution
01
Isolate the Absolute Value Expression
Start with the inequality \( 0 \leq |6x - 3| - 5 \). The first step is to isolate the absolute value expression on one side. To do this, add 5 to both sides of the inequality to remove the -5.\[0 + 5 \leq |6x - 3|\]This simplifies to:\[5 \leq |6x - 3|\]
02
Understand the Absolute Value Inequality
The inequality \( 5 \leq |6x - 3| \) states that the distance of \( 6x - 3 \) from 0 is at least 5. Absolute value inequalities of the form \( |A| \geq B \) can be split into two inequalities: \( A \geq B \) or \( A \leq -B \).
03
Split into Two Inequalities
Split \( |6x - 3| \geq 5 \) into:1. \( 6x - 3 \geq 5 \)2. \( 6x - 3 \leq -5 \)
04
Solve Each Inequality
Let's solve both inequalities for \( x \):**1. Solve** \( 6x - 3 \geq 5 \):- Add 3 to both sides:\[ 6x \geq 8 \]- Divide both sides by 6:\[ x \geq \frac{4}{3} \]**2. Solve** \( 6x - 3 \leq -5 \):- Add 3 to both sides:\[ 6x \leq -2 \]- Divide both sides by 6:\[ x \leq -\frac{1}{3} \]
05
Combine the Solutions
The solution to the inequality \( |6x - 3| \geq 5 \) is the combination of the solutions to both inequalities in Step 4. Thus, \( x \geq \frac{4}{3} \) or \( x \leq -\frac{1}{3} \).
06
Express in Interval Notation
Write the solution set in interval notation. Since there are two separate parts to the solution, the interval notation is:\[ (-\infty, -\frac{1}{3}] \cup [\frac{4}{3}, \infty) \]
07
Graph the Solution Set
To graph the solution set, draw a number line. Shade the region to the left of \(-\frac{1}{3}\), including \(-\frac{1}{3}\), using a closed dot. Then shade the region to the right of \(\frac{4}{3}\), including \(\frac{4}{3}\), also using a closed dot. This represents the values of \(x\) that satisfy the inequality.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Interval Notation Explained
Imagine interval notation as a simple way to describe a set of numbers that form a solution to an inequality. It's like writing a shortcut for the numbers that work. Let's break down the interval notation:
- Around brackets: "[ ]" means 'inclusive', showing the number is part of the solution.
- Round brackets: "( )" means 'exclusive', meaning the number itself isn't part of the solution.
- Infinity symbol (∞): Used to express that the values continue indefinitely in one direction.
- "\((-\infty, -\frac{1}{3}]\)" represents all numbers less than or equal to \(-\frac{1}{3}\).
- "\([\frac{4}{3}, \infty)\)" represents all numbersgreater than or equal to \(\frac{4}{3}\).
- The union symbol "\(\cup\)" is like saying "or"; either condition satisfies the inequality.
Graphing Inequalities: Visualizing Solutions
Graphing inequalities helps you visually interpret the solution on a number line. This is a powerful tool because it shows all possible numbers that solve the inequality. For the inequality determined in the original exercise, here's how you graph it:First, identify the critical points, which are \(-\frac{1}{3}\) and \(\frac{4}{3}\).
- Place a closed dot on \(-\frac{1}{3}\) because the inequality includes this point ("\([\)]").
- Shade the entire line to the left of this point, showing values less than or equal to \(-\frac{1}{3}\).
- Again, shade the entire line to the right of this point, expressing values greater than or equal to \(\frac{4}{3}\).
Solving Absolute Value Inequalities
Solving absolute value inequalities might seem tricky at first, but there's a straightforward approach to tackle them effectively. Absolute value refers to the distance a number is from zero, so it’s always positive or zero. Here's how to handle inequalities with absolute values, such as \(|6x - 3| \geq 5\):
- Start by isolating the absolute value expression. Here, it’s already isolated as \(5 \leq |6x - 3|\).
- This inequality \(|A| \geq B\) can be split into two separate inequalities: \(A \geq B\) and \(A \leq -B\).
- Convert \(|6x - 3| \geq 5\) into two inequalities:
- \(6x - 3 \geq 5\)
- \(6x - 3 \leq -5\)
- For \(6x - 3 \geq 5\), solve \(x \geq \frac{4}{3}\).
- For \(6x - 3 \leq -5\), solve \(x \leq -\frac{1}{3}\).