/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 57 Factor difference of cubes. \(... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Factor difference of cubes. \(64 t^{6}-27 v^{3}\)

Short Answer

Expert verified
The factored form of the expression \(64 t^{6} - 27 v^{3}\) is \((4t^2 - 3v)(16t^4 + 12t^2v + 9v^2)\).

Step by step solution

01

Identify the Difference of Cubes Formula

The formula for factoring the difference of cubes is: \[ a^3 - b^3 = (a - b)(a^2 + ab + b^2) \]We need to express the given expression \(64t^6 - 27v^3\) in the form of \(a^3 - b^3\).
02

Rewrite Each Term as a Cube

Recognize the terms as cubes: \(64t^6 = (4t^2)^3\) and \(27v^3 = (3v)^3\). The expression can be rewritten as: \[ (4t^2)^3 - (3v)^3 \]
03

Substitute into the Difference of Cubes Formula

Now substitute \(a = 4t^2\) and \(b = 3v\) into the difference of cubes formula: \[ (4t^2 - 3v)((4t^2)^2 + (4t^2)(3v) + (3v)^2) \]
04

Simplify the Expression

Calculate each term in the expression:- \((4t^2)^2 = 16t^4\)- \((4t^2)(3v) = 12t^2v\)- \((3v)^2 = 9v^2\)The expression becomes:\[ (4t^2 - 3v)(16t^4 + 12t^2v + 9v^2) \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Polynomial Factorization
When dealing with algebraic expressions, polynomial factorization is a powerful tool to simplify and manipulate these expressions. Factorization involves rewriting a polynomial as a product of simpler polynomials. In simpler terms, it means breaking down a complex expression into simpler parts that multiply together to give the original expression.
  • Factorization helps in solving polynomial equations by simplifying them.
  • It reveals the roots (or zeros) of the polynomial, which are the values for which the polynomial equals zero.
  • By understanding factorization, one can also sketch the graph of a polynomial function more easily.
Learning to factor different types of polynomials, such as quadratics, difference of squares, and difference of cubes, expands your toolkit for tackling complex algebraic expressions. In our example, we’re applying the special technique of 'difference of cubes' to factor the given polynomial. Identifying patterns in the terms of the polynomial is often the first step in successful factorization.
Algebraic Expressions
Algebraic expressions are mathematical phrases that can include numbers, variables, and operations such as addition, subtraction, multiplication, and division. These expressions are foundational in algebra and are used to represent real-world situations in a concise mathematical form.
  • Algebraic expressions can be simplified, evaluated, or factored.
  • Expressions are denoted by variables such as 't' or 'v' in our exercise, which represent values that can change.
  • Simplifying these expressions involves combining like terms and using arithmetic operations.
In tackling our difference of cubes problem, we identify components of the expression that can be rewritten and simplified. Understanding how to manipulate variables and exponents in algebraic expressions is key to solving these types of problems. By factorizing, we break down the expression into parts that are easier to work with, ultimately revealing new insights and solutions.
Difference of Cubes Formula
The difference of cubes formula is a specific polynomial identity used in factorization. It is particularly handy when you observe terms in an expression that are cubes of other terms. The formula itself is:
\[ a^3 - b^3 = (a - b)(a^2 + ab + b^2) \]
  • This formula helps to quickly factor expressions comprised of cubes.
  • Identifying 'a' and 'b' from the expression is the crucial first step.
  • After identification, the expression can be systematically broken down using the formula.
In the exercise example, the expression \(64t^6 - 27v^3\) was rewritten in the form of \((4t^2)^3 - (3v)^3\). Recognizing these cube structures allows us to apply the formula smoothly. Implementing this, each component of \((4t^2 - 3v)(16t^4 + 12t^2v + 9v^2)\) can be derived, which helps simplify even more complex expressions efficiently. Knowing and applying this formula can be a significant advantage in algebra.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

$$\text { Simplify: }\left[\left(x^{-1}+1\right)^{-1}+1\right]^{-1}$$

According to data from Netcraft Web Server Survey, the total number of active websites available over the Internet (in millions) is approximated by the function \(w(t)=12.67 t+29.15,\) where \(t\) is the number of years after \(2005 .\) Approximately how many active websites were there in \(2011 ?\)

Home Construction. In a proposal to some clients, a housing contractor listed the following costs:$$ \begin{array}{lr} \text { Fees, permits, miscellaneous } & \$ 12,000 \\ \hline \text { Construction, per square foot } & \$ 95 \\ \hline \end{array} $$ a. Write a linear function that the clients could use to determine the cost of building a home having \(f\) square feet. b. Find the cost to build a home having \(1,950\) square feet.

Breathing Capacity. When fitness instructors prescribe exercise workouts for elderly patients, they must take into account age-related loss of lung function. Studies show that the percent of remaining breathing capacity for someone over 30 years old can be modeled by a linear function. (Source: alsearsmd.com) a. At 35 years of age, approximately \(90 \%\) of maximal breathing capacity remains and at 55 years of age, approximately \(66 \%\) of maximal breathing capacity remains. Let \(a\) be the age of a patient and \(L\) be the percent of her maximal breathing capacity that remains. Write a linear function \(L(a)\) to model this situation. b. Use your answer to part a to estimate the percent of maximal breathing capacity that remains in an 80 -year-old.

In the following problems, simplify each expression by performing the indicated operations and solve each equation. $$\frac{2}{x-1}-\frac{2 x}{x^{2}-1}-\frac{x}{x^{2}+2 x+1}$$

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.