Chapter 8: Problem 11
Let \(f(x)=\frac{2 x+1}{x^{2}+3 x-4} .\) Find a. \(f(0)\) b. \(f(2)\) c. \(f(1)\)
Short Answer
Expert verified
a. \( f(0) = -\frac{1}{4} \); b. \( f(2) = \frac{5}{6} \); c. \( f(1) \) is undefined.
Step by step solution
01
Understanding the Function
The given function is \( f(x) = \frac{2x + 1}{x^2 + 3x - 4} \). It is a rational function, which means it is the division of two polynomials. To find the value of the function at a specific point, we substitute the given value of \( x \) into the function and simplify.
02
Calculating \( f(0) \)
To find \( f(0) \), substitute \( x = 0 \) into the function: \[ f(0) = \frac{2(0) + 1}{0^2 + 3(0) - 4} = \frac{1}{-4}. \] So, \( f(0) = -\frac{1}{4} \).
03
Calculating \( f(2) \)
To find \( f(2) \), substitute \( x = 2 \) into the function: \[ f(2) = \frac{2(2) + 1}{2^2 + 3(2) - 4} = \frac{5}{6}. \] So, \( f(2) = \frac{5}{6} \).
04
Calculating \( f(1) \)
To find \( f(1) \), substitute \( x = 1 \) into the function: \[ f(1) = \frac{2(1) + 1}{1^2 + 3(1) - 4} = \frac{3}{0}. \] Since the function involves division by zero, \( f(1) \) is undefined.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Polynomials
Polynomials are a fundamental concept in algebra and calculus, and they form the backbone of many mathematical functions, including rational functions. A polynomial is an algebraic expression consisting of variables, coefficients, and non-negative integer exponents, all combined using addition, subtraction, and multiplication operations. Polynomials can be classified based on the degree—the highest power of the variable present in the expression. For example:
- A linear polynomial has the form: \( ax + b \).
- A quadratic polynomial has the form: \( ax^2 + bx + c \).
- A cubic polynomial has the form: \( ax^3 + bx^2 + cx + d \).
Division by Zero
A division by zero occurs when the denominator of a rational expression equals zero, which is undefined in mathematics. This situation leads to indeterminate forms that cannot be evaluated using standard arithmetic rules. Consider again the function \( f(x) = \frac{2x + 1}{x^2 + 3x - 4} \). To find out where division by zero might occur, set the denominator to zero and solve for \( x \):
- \( x^2 + 3x - 4 = 0 \)
- Factoring gives \((x - 1)(x + 4) = 0\).
- This results in \( x = 1 \) and \( x = -4 \).
Evaluating Functions
Evaluating functions involves substituting a specific value in for the variable in a given function and simplifying the expression to find the result. This process is significant for understanding the behavior of functions at particular points. For example, with the function \( f(x) = \frac{2x + 1}{x^2 + 3x - 4} \), consider evaluating \( f(0) \), \( f(2) \), and \( f(1) \):
- For \( f(0) \): Substitute \( x = 0 \) and simplify to get \( f(0) = -\frac{1}{4} \).
- For \( f(2) \): Substitute \( x = 2 \) yielding \( f(2) = \frac{5}{6} \).
- For \( f(1) \): Substitute \( x = 1 \) which results in \( \frac{3}{0} \), an undefined expression due to division by zero.