Chapter 7: Problem 57
Solve each proportion. $$ \frac{x-1}{x+1}=\frac{2}{3 x} $$
Short Answer
Expert verified
The solutions are \(x = 2\) and \(x = -\frac{1}{3}\).
Step by step solution
01
Cross-multiply Both Sides
To solve the proportion \( \frac{x-1}{x+1} = \frac{2}{3x} \), start by cross-multiplying. This gives us:\[(x-1) \cdot (3x) = 2 \cdot (x+1)\]This results in the equation:\[3x(x-1) = 2(x+1)\]
02
Expand Both Sides
Expand both sides of the equation obtained:Left side: \[3x(x-1) = 3x^2 - 3x\]Right side: \[2(x+1) = 2x + 2\]This results in the equation:\[3x^2 - 3x = 2x + 2\]
03
Bring All Terms to One Side
Rearrange the equation to bring all terms to one side, creating a quadratic equation:\[3x^2 - 3x - 2x - 2 = 0\]Simplify this to:\[3x^2 - 5x - 2 = 0\]
04
Solve the Quadratic Equation
Now solve the quadratic equation \(3x^2 - 5x - 2 = 0\). Use the quadratic formula, \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \), where \(a = 3\), \(b = -5\), and \(c = -2\):Calculate the discriminant:\[b^2 - 4ac = (-5)^2 - 4 \cdot 3 \cdot (-2) = 25 + 24 = 49\]Apply the quadratic formula:\[x = \frac{-(-5) \pm \sqrt{49}}{2 \cdot 3} = \frac{5 \pm 7}{6}\]
05
Find Solutions
Calculate the two possible values for \(x\):1. \(x = \frac{5 + 7}{6} = 2\)2. \(x = \frac{5 - 7}{6} = -\frac{1}{3}\)Thus, the solutions are \(x = 2\) and \(x = -\frac{1}{3}\).
06
Verify the Solutions
To ensure no extraneous solutions, check that the solutions satisfy the original proportion:1. For \(x = 2\): \(\frac{2-1}{2+1} = \frac{1}{3}\) and \(\frac{2}{3 \times 2} = \frac{1}{3}\); both sides are equal.2. For \(x = -\frac{1}{3}\): Substitute into \(\frac{x-1}{x+1}\) and \(\frac{2}{3x}\) and verify they equate. This requires additional calculation to confirm equality.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Cross-Multiplication
Cross-multiplication is a simple and effective method used to solve proportions, which are equations that state that two ratios are equivalent. Imagine this scenario: you have a proportion, like the equation \( \frac{x-1}{x+1} = \frac{2}{3x} \). Here, you want to find out what value of \( x \) makes the two ratios equal.To do this, follow the step of cross-multiplication:
- Multiply the numerator of the first ratio by the denominator of the second ratio.
- Multiply the numerator of the second ratio by the denominator of the first ratio.
- Set the two products equal to each other.
- Left side: \( (x-1)\cdot(3x) \).
- Right side: \(2\cdot(x+1) \).
Quadratic Equations
A quadratic equation is a vital concept in algebra. It's a type of polynomial equation and its standard form looks like this: \( ax^2 + bx + c = 0 \). Here, \( a \), \( b \), and \( c \) are coefficients with a rule that \( a eq 0 \), and \( x \) represents an unknown variable. Quadratics can often have two solutions because they are expressions of parabolas that might intersect the x-axis at two points.In our problem, after cross-multiplying and simplifying, we transformed the equation into:
- \(3x^2 - 5x - 2 = 0\)
- Factoring the expression if possible.
- Completing the square.
- Using the quadratic formula, which we apply here.
Quadratic Formula
The quadratic formula is an essential tool for solving quadratic equations when factoring is complex or impossible. The formula is:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]Here:
- \( a \), \( b \), and \( c \) are the coefficients from your quadratic equation, \( ax^2 + bx + c = 0 \).
- \( \pm \) signifies that there are generally two solutions; one using addition and the other using subtraction.
- The term under the square root, \( b^2 - 4ac \), is called the discriminant.
- \( a = 3 \), \( b = -5 \), \( c = -2 \).
- Finding the discriminant: \( (-5)^2 - 4 \times 3 \times (-2) = 49 \).
- Plugging values into the formula gives solutions \( x = \frac{5 \pm 7}{6} \), which simplifies to \( x = 2 \) and \( x = -\frac{1}{3} \).