Chapter 6: Problem 92
Solve each equation. $$ 5 f(5 f-16)=-15 $$
Short Answer
Expert verified
The solutions are \( f = 3 \) and \( f = 0.2 \).
Step by step solution
01
Set the Equation to Zero
First, rewrite the original equation by moving all terms to one side of the equation to set it to zero: \[ 5f(5f - 16) + 15 = 0 \].
02
Expand the Equation
Expand the terms in the equation: \[ 5f imes 5f = 25f^2 \] and \[ 5f imes -16 = -80f \]. So the equation becomes \[ 25f^2 - 80f + 15 = 0 \].
03
Use the Quadratic Formula
To solve the quadratic equation \[ 25f^2 - 80f + 15 = 0 \], use the quadratic formula: \[ f = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \], where \( a = 25 \), \( b = -80 \), and \( c = 15 \).
04
Calculate the Discriminant
Calculate the discriminant, \( b^2 - 4ac \): \[ (-80)^2 - (4 imes 25 imes 15) = 6400 - 1500 = 4900 \].
05
Solve for Roots
Use the discriminant to find the roots: \[ f = \frac{80 \pm \sqrt{4900}}{50} \]. Calculate \( \sqrt{4900} = 70 \). Substitute into the formula to get: \[ f = \frac{80 \pm 70}{50} \].
06
Calculate Each Solution
Solve for \( f \): - First solution: \[ f = \frac{80 + 70}{50} = 3 \].- Second solution: \[ f = \frac{80 - 70}{50} = 0.2 \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool that helps us solve quadratic equations, which are polynomials of degree two. These equations commonly look like this:
To find the solutions, or "roots," we use the quadratic formula:
- \[ ax^2 + bx + c = 0 \]
To find the solutions, or "roots," we use the quadratic formula:
- \[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]
Steps for Using the Quadratic Formula
- First, identify the coefficients \( a \), \( b \), and \( c \) from the quadratic equation.
- Calculate the discriminant, which is the portion under the square root: \( b^2 - 4ac \).
- Substitute the values into the quadratic formula and solve for \( x \).
Discriminant
The discriminant is a key component in the quadratic formula and has an essential role in determining the nature of the roots. It is given by the expression:
- \[ b^2 - 4ac \]
Understanding the Discriminant
The value of the discriminant provides crucial information:- If it is positive, there are two distinct real roots.
- If it is zero, there is exactly one real root, known as a repeated or double root.
- If it is negative, the equation has no real roots, but two complex roots.
Roots of a Quadratic Equation
Finding the roots of a quadratic equation means solving for the values of \( x \) that satisfy the equation. These roots are the solutions where the equation equals zero.For example, in our equation
- \[ 25f^2 - 80f + 15 = 0 \]
Calculating the Roots
In our example:- First solution: Substitute and solve \( \frac{80 + 70}{50} = 3 \)
- Second solution: Substitute and solve \( \frac{80 - 70}{50} = 0.2 \)