Chapter 6: Problem 53
The following is a list of random factoring problems. Factor each expression. If an expression is not factorable, write "prime." See Examples 1-5. $$ 4 x^{2} y^{2}+4 x y^{2}+y^{2} $$
Short Answer
Expert verified
The expression factors to \( y^2(2x + 1)^2 \).
Step by step solution
01
Identify Common Factors
Look at the expression \(4x^2y^2 + 4xy^2 + y^2\). Notice that each term contains a \(y^2\). Factor \(y^2\) out of the entire expression.\[ y^2(4x^2 + 4x + 1) \]
02
Factor the Quadratic Expression
Now focus on the quadratic expression inside the parentheses: \(4x^2 + 4x + 1\). This expression is in the form of a trinomial quadratic equation \(ax^2 + bx + c\).
03
Apply the Quadratic Formula
Since factoring by inspection or other methods might not be straightforward, let's find the roots, if any, by using the quadratic formula:\[ x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \]Substitute \(a = 4\), \(b = 4\), and \(c = 1\):\[ x = \frac{-4 \pm \sqrt{4^2 - 4 \cdot 4 \cdot 1}}{2 \cdot 4} \]\[ x = \frac{-4 \pm \sqrt{16 - 16}}{8} \]\[ x = \frac{-4 \pm 0}{8} \]\[ x = -\frac{1}{2} \]
04
Factor Using the Roots
Since the quadratic has a double root \( x = -\frac{1}{2} \), the expression \(4x^2 + 4x + 1\) can be factored as:\[ (2x + 1)^2 \]
05
Write the Final Factored Expression
Combine the factors obtained in previous steps: \(y^2(2x + 1)^2\). Therefore, the completely factored expression for the original problem is:\[ y^2(2x + 1)^2 \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Formula
The quadratic formula is a powerful tool used to solve quadratic equations of the form \(ax^2 + bx + c = 0\). This equation can be factored or solved using the formula:
The result gives you the roots or solutions of the equation.
To illustrate, let's take the quadratic expression \(4x^2 + 4x + 1\) from our example. Here, identify the coefficients as \(a = 4\), \(b = 4\), and \(c = 1\). Plug these into the quadratic formula:
- \( x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \)
The result gives you the roots or solutions of the equation.
To illustrate, let's take the quadratic expression \(4x^2 + 4x + 1\) from our example. Here, identify the coefficients as \(a = 4\), \(b = 4\), and \(c = 1\). Plug these into the quadratic formula:
- \(x = \frac{-4 \pm \sqrt{4^2 - 4 \cdot 4 \cdot 1}}{2 \cdot 4}\)
- Simplifying the equation results in: \( x = -\frac{1}{2} \)
Trinomial Quadratic Equation
A trinomial quadratic equation is an equation of the form \(ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants. It features three terms: one squared term, one linear term, and a constant term.
The equation from our exercise, \(4x^2 + 4x + 1\), falls under this category.
Instead, using the quadratic formula was effective in determining the root \(x = -\frac{1}{2}\). Once you've identified the root through the formula, you can express the trinomial in factored form, which was found in our solution to be \((2x + 1)^2\).
The equation from our exercise, \(4x^2 + 4x + 1\), falls under this category.
- *"Trinomial"* implies three terms are being considered.
- Factoring, if possible;
- Using the quadratic formula when factoring is complex or not straightforward.
Instead, using the quadratic formula was effective in determining the root \(x = -\frac{1}{2}\). Once you've identified the root through the formula, you can express the trinomial in factored form, which was found in our solution to be \((2x + 1)^2\).
Common Factor Identification
Identifying common factors is often the first step in simplifying or factoring expressions. When factoring expressions, always check if a common factor is present in all terms.
In the example \(4x^2y^2 + 4xy^2 + y^2\), notice that each term contains a factor of \(y^2\). By factoring out \(y^2\), the expression simplifies to:
Identification of common factors not only simplifies the problem but also sets a solid foundation for solving or factoring more sophisticated algebraic expressions.
In the example \(4x^2y^2 + 4xy^2 + y^2\), notice that each term contains a factor of \(y^2\). By factoring out \(y^2\), the expression simplifies to:
- \(y^2(4x^2 + 4x + 1)\)
- Looking at coefficients and variable powers.shared among all terms;
- Determining the highest power of each shared variable.
Identification of common factors not only simplifies the problem but also sets a solid foundation for solving or factoring more sophisticated algebraic expressions.