/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 106 Factor the expression in part a ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Factor the expression in part a and solve the equation in part \(\boldsymbol{b}\) a. \(x^{2}-36\) b. \(x^{2}-36=0\)

Short Answer

Expert verified
a. \((x - 6)(x + 6)\); b. \(x = 6\) and \(x = -6\).

Step by step solution

01

Understand the Type of Expression

The given expression \(x^2 - 36\) is a classic example of a difference of squares, which has the formula \(a^2 - b^2 = (a - b)(a + b)\). In this case, \(a = x\) and \(b = 6\) because \(36 = 6^2\).
02

Apply the Difference of Squares Formula

Using the difference of squares formula, we can factor \(x^2 - 36\) as follows:\[x^2 - 36 = (x - 6)(x + 6)\]
03

Set the Equation to Zero

For part b, we start with the equation \(x^2 - 36 = 0\). Using the factorization from Step 2, the equation becomes \((x - 6)(x + 6) = 0\).
04

Apply the Zero Product Property

The Zero Product Property states that if \(ab = 0\), then either \(a = 0\) or \(b = 0\). Here, \((x - 6)\) and \((x + 6)\) are the factors, so set each to 0:1. \(x - 6 = 0\)2. \(x + 6 = 0\)
05

Solve for x

Solve the equations from Step 4:1. For \(x - 6 = 0\), add 6 to both sides to get \(x = 6\).2. For \(x + 6 = 0\), subtract 6 from both sides to get \(x = -6\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Difference of Squares
In algebra, the **difference of squares** is a powerful tool for factoring expressions. This concept applies when you have an expression of the form \(a^2 - b^2\). Here, \(a\) and \(b\) represent any expressions or numbers. The beauty of this technique is that it simplifies into a multiplication of two binomials: \((a - b)(a + b)\).
For example, in the expression \(x^2 - 36\), \(x^2\) can be seen as \((x)^2\) and 36 as \(6^2\). Recognizing this makes it clear that you are dealing with a difference of squares. Simply apply the formula:
  • Identify \(a\) and \(b\) from the expression such that \(a^2 = x^2\) and \(b^2 = 36\).
  • Here, \(a = x\) and \(b = 6\).
  • Apply the formula: \(x^2 - 36 = (x - 6)(x + 6)\).
By leveraging this technique, you can quickly reduce the expression to a product of simpler factors.
Zero Product Property
The **Zero Product Property** is a fundamental principle in algebra that comes in handy when solving equations. It tells us that if a product of two factors equals zero, then at least one of the factors must be zero. In algebraic terms, if \(ab = 0\), then either \(a = 0\) or \(b = 0\).
When you use factoring to solve quadratic equations, such as in the equation \(x^2 - 36 = 0\), it often leads us to apply this property. Once we factor \(x^2 - 36\) into \((x - 6)(x + 6) = 0\), the next step is to set each factor equal to zero:
  • \(x - 6 = 0\)
  • \(x + 6 = 0\)
By doing this, you isolate possible solutions for \(x\). Each value of \(x\) which satisfies these equations is a solution to the original quadratic equation. Understanding and applying the Zero Product Property makes finding solutions straightforward.
Solving Quadratic Equations
**Solving quadratic equations** often starts with recognizing the type of quadratic and deciding on the best strategy for solving it. One effective approach is factoring, especially when dealing with equations that simplify into a form easily recognizable, such as a difference of squares.
Let's consider the quadratic equation from our exercise: \(x^2 - 36 = 0\). Here's how you solve it step by step:
  • Recognize the form: Notice that \(x^2 - 36\) is a difference of squares which allows factoring to \((x - 6)(x + 6)\).
  • Set each factor equal to zero using the Zero Product Property:
    • \(x - 6 = 0\)
    • \(x + 6 = 0\)
  • Solve each simple equation:
    • For \(x - 6 = 0\): Add 6 to both sides to find \(x = 6\).
    • For \(x + 6 = 0\): Subtract 6 from both sides to find \(x = -6\).
Therefore, the solutions to \(x^2 - 36 = 0\) are \(x = 6\) and \(x = -6\). This method of solving by factoring is efficient and widely used for quadratics that can be factored easily.

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