Chapter 6: Problem 103
Factor the expression in part a and solve the equation in part \(\boldsymbol{b}\) a. \(x^{2}+4 x-21\) b. \(x^{2}+4 x-21=0\)
Short Answer
Expert verified
The factors are \((x - 3)(x + 7)\), and the solutions are \(x = 3\) and \(x = -7\).
Step by step solution
01
Identify the Quadratic Expression
The expression given is a quadratic expression in the form of \(ax^2 + bx + c\), where \(a = 1\), \(b = 4\), and \(c = -21\).
02
Find Two Numbers That Multiply to \(-21\) and Add to \(4\)
Look for two numbers that multiply to \(ac = 1 \times -21 = -21\) and add to \(b = 4\). The numbers \(7\) and \(-3\) fit these requirements because \(7 imes (-3) = -21\) and \(7 + (-3) = 4\).
03
Factor the Expression
Rewrite the expression \(x^2 + 4x - 21\) using the numbers 7 and -3 to break up the middle term: \(x^2 + 7x - 3x - 21\). Group the terms: \((x^2 + 7x) + (-3x - 21)\). Factor out the greatest common factors: \(x(x + 7) - 3(x + 7)\). Lastly, factor by grouping to get \((x - 3)(x + 7)\).
04
Set the Equation to Zero
Now solve the equation \(x^2 + 4x - 21 = 0\) by setting each factor equal to zero: \(x - 3 = 0\) and \(x + 7 = 0\).
05
Solve Each Equation
Solve the equations \(x - 3 = 0\) and \(x + 7 = 0\) for \(x\). \(x - 3 = 0\) gives \(x = 3\); \(x + 7 = 0\) gives \(x = -7\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Factoring Quadratics
Factoring quadratics is a fundamental algebraic skill that involves breaking down a quadratic expression into simpler, multiplicative components called factors. Let's explore the method for factoring the expression given in the problem, which is \(x^2 + 4x - 21\).
For quadratic expressions in the form \(ax^2 + bx + c\), we start by identifying the coefficients \(a = 1\), \(b = 4\), and \(c = -21\).
For quadratic expressions in the form \(ax^2 + bx + c\), we start by identifying the coefficients \(a = 1\), \(b = 4\), and \(c = -21\).
- The next step is to find two numbers that multiply to \(-21\) (since \(a \times c = 1 \times -21\)) and add up to \(4\), the coefficient of the linear term.
- In this example, the numbers \(7\) and \(-3\) are the right pair: \(7 \times -3 = -21\) and \(7 + (-3) = 4\).
- Group the terms to have: \((x^2 + 7x) + (-3x - 21)\).
- Factor out the greatest common factors: \(x(x + 7) - 3(x + 7)\).
- Finally, factor by grouping to get the expression fully factored: \((x - 3)(x + 7)\).
Solving Quadratic Equations
Solving quadratic equations is the process of finding the values for the variable that make the equation true. The given equation is \(x^2 + 4x - 21 = 0\). To solve it, we will use the factored form from the previous section, \((x - 3)(x + 7)\).
The principle is simple: If a product of two factors equals zero, then at least one of the factors must be zero. This is known as the zero-product property, and it provides us with two smaller equations to solve:
The principle is simple: If a product of two factors equals zero, then at least one of the factors must be zero. This is known as the zero-product property, and it provides us with two smaller equations to solve:
- Set \(x - 3 = 0\): Solve for \(x\) by adding \(3\) to both sides giving \(x = 3\).
- Set \(x + 7 = 0\): Solve for \(x\) by subtracting \(7\) from both sides providing \(x = -7\).
Polynomial Factoring
Polynomial factoring is a broader concept that forms the backbone of algebraic manipulation and involves expressing a polynomial as a product of simpler, non-factorizable polynomials. In the realm of quadratics, such as \(x^2 + 4x - 21\), it specifically involves breaking it down into binomials, as we've seen in this exercise.
Polynomials can have varying degrees, and each degree can affect how you approach factoring:
Polynomials can have varying degrees, and each degree can affect how you approach factoring:
- For quadratics (degree 2), the standard factorization method includes finding two numbers that fulfill both the multiplication and addition conditions for the coefficients \(a, b, \text{ and } c\).
- Higher-degree polynomials might require more advanced techniques, including synthetic division, long division, or using the rational root theorem to find factors.