Chapter 5: Problem 60
Perform the operations. $$ 4 y(3 y+4)(3 y+4) $$
Short Answer
Expert verified
The expression simplifies to \(36y^3 + 96y^2 + 64y\).
Step by step solution
01
Understand the Expression
The given expression is \(4y(3y+4)(3y+4)\). This represents the multiplication of three terms: \(4y\), and the binomial \((3y+4)\) squared.
02
Expand the Squared Binomial
Before proceeding, expand the square of the binomial: \((3y+4)^2 = (3y+4)(3y+4)\). Use the formula \((a+b)^2 = a^2 + 2ab + b^2\). Here, \(a = 3y\) and \(b = 4\).
03
Calculate \((3y+4)^2\)
Applying the square formula, \((3y+4)^2 = (3y)^2 + 2(3y)(4) + 4^2 = 9y^2 + 24y + 16\). The expression becomes \(4y(9y^2 + 24y + 16)\).
04
Distribute \(4y\) Across Each Term
Now distribute \(4y\) into each term of the polynomial \(9y^2 + 24y + 16\). This means calculating each of the following: \(4y \cdot 9y^2\), \(4y \cdot 24y\), and \(4y \cdot 16\).
05
Compute Each Term
- For \(4y \cdot 9y^2\), multiply coefficients \(4 \cdot 9 = 36\) and powers of \(y\): \(y^1 \cdot y^2 = y^3\), resulting in \(36y^3\).- For \(4y \cdot 24y\), multiply coefficients \(4 \cdot 24 = 96\) and powers: \(y \cdot y = y^2\), resulting in \(96y^2\).- For \(4y \cdot 16\), multiply \(4 \cdot 16 = 64\), resulting in \(64y\).
06
Write the Final Expression
Combine all computed terms to write the final expanded expression: \(36y^3 + 96y^2 + 64y\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Expansion
When dealing with binomials raised to a power, such as \( (3y+4)^2 \), we utilize a technique known as binomial expansion. A binomial is simply an algebraic expression containing two terms, in our case, \( 3y \) and \( 4 \).
The formula used for expansion is \( (a+b)^2 = a^2 + 2ab + b^2 \), where \( a \) and \( b \) are the two terms of the binomial.
The formula used for expansion is \( (a+b)^2 = a^2 + 2ab + b^2 \), where \( a \) and \( b \) are the two terms of the binomial.
- Step 1: Square the first term, which is \( (3y)^2 = 9y^2 \).
- Step 2: Multiply the two terms together and then double the result: \( 2 \times (3y) \times 4 = 24y \).
- Step 3: Square the second term: \( 4^2 = 16 \).
Distributive Property
The Distributive Property is a fundamental algebraic principle used when multiplying a single term across a polynomial. In our exercise, we apply the Distributive Property to \( 4y \) and the polynomial \( 9y^2 + 24y + 16 \).
This property states that when multiplying a term by a sum, distribute that term to each addend of the sum. In simpler words:
This property states that when multiplying a term by a sum, distribute that term to each addend of the sum. In simpler words:
- Multiply: Apply \( 4y \) to each term of the polynomial separately.
- For example, \( 4y \times 9y^2 \) becomes \( 36y^3 \).
- Then, \( 4y \times 24y \) gives \( 96y^2 \).
- Lastly, \( 4y \times 16 \) results in \( 64y \).
Algebraic Expressions
Algebraic expressions form the backbone of algebra with variables, coefficients, and operations. When you look at the expression \( 4y(3y+4)(3y+4) \), several key components form the structure:
- Variables: Symbols like \( y \) represent unknown quantities that can change.
- Coefficients: These are numbers that multiply the variables, such as \( 4 \) in \( 4y \).
- Constants: Fixed values like \( 4 \) in the binomial \( 3y+4 \).