Chapter 4: Problem 92
Construct a system of two linear equations that has a solution of \((-2,6)\)
Short Answer
Expert verified
The system is:
1. \(y = x + 8\)
2. \(y = -2x + 2\)
Step by step solution
01
Understanding the Solution Set
The solution set (-2, 6) means that the point (-2, 6) is where two lines intersect, satisfying both equations in the system. This means when we plug in x = -2 and y = 6 into each equation, they both hold true.
02
Choosing a Line Form
Let's use the slope-intercept form of a line, which is y = mx + c, where m is the slope and c is the y-intercept. We'll construct two different lines that intersect at x = -2 and y = 6.
03
Constructing the First Equation
Choose the slope m_1 = 1. Using the point-slope form y - y_1 = m(x - x_1), where (x_1, y_1) = (-2, 6), we write y - 6 = 1(x + 2). Simplifying, we get y = x + 8.
04
Constructing the Second Equation
Choose a different slope, m_2 = -2. Using the point-slope form again, write y - 6 = -2(x + 2). Simplifying this equation, we obtain y = -2x + 2.
05
Verifying the Solution
Substitute x = -2 into both equations y = x + 8 and y = -2x + 2. For the first equation, y = -2 + 8 = 6, and for the second equation, y = -2(-2) + 2 = 6. Both check out, meaning both lines intersect at (-2, 6).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Solution of a System
When you have two or more equations, and you are trying to find a common solution, you are solving a system of equations. A solution to a system of linear equations is a point where all the equations are satisfied simultaneously. This means it is the point of intersection of the lines represented by these equations.
This point of intersection is the \((-2, 6)\) in our exercise. Therefore, when you plug in \(-2\) for \ x \ and \ 6 \ for \ y \ into each equation of the system, both equations will become true. So, the key takeaway is:
Finding this solution involves constructing and verifying equations to ensure they both intersect at this point.
This point of intersection is the \((-2, 6)\) in our exercise. Therefore, when you plug in \(-2\) for \ x \ and \ 6 \ for \ y \ into each equation of the system, both equations will become true. So, the key takeaway is:
- The solution is the point where all lines intersect.
- Both \ x \ and \ y \ values must satisfy all equations.
Finding this solution involves constructing and verifying equations to ensure they both intersect at this point.
Slope-Intercept Form
The slope-intercept form of a linear equation is \(y = mx + c\). Here 'm' is the slope of the line, and 'c' is the y-intercept. This form is very helpful in quickly identifying how a line behaves and where it crosses the y-axis.
Consider the line \(y = x + 8\):
This form is simple and efficient for graphing and understanding the direction and position of the line. In our example, both lines are written in slope-intercept form, making it easy to grasp their intersections and verify solutions.
Consider the line \(y = x + 8\):
- The slope: \(m = 1\) shows that for every step we move along the x-axis, we move an equal step up on the y-axis.
- The y-intercept: \(c = 8\) tells us that the line crosses the y-axis at \ y = 8 \.
This form is simple and efficient for graphing and understanding the direction and position of the line. In our example, both lines are written in slope-intercept form, making it easy to grasp their intersections and verify solutions.
Point-Slope Form
The point-slope form of a linear equation is given by \(y - y_1 = m(x - x_1)\). This is useful when you know a point on the line \((x_1, y_1)\) and the slope 'm'. You can construct the equation of the line using this information.
For example, if we take \(x_1 = -2\) and \(y_1 = 6\) with slope \(m_1 = 1\), we can form:
\[ y - 6 = 1(x + 2) \] Simplifying this, it transforms into the slope-intercept form and becomes \(y = x + 8\).
The point-slope form is versatile and a handy tool in constructing mathematical representations of linear scenarios.
For example, if we take \(x_1 = -2\) and \(y_1 = 6\) with slope \(m_1 = 1\), we can form:
\[ y - 6 = 1(x + 2) \] Simplifying this, it transforms into the slope-intercept form and becomes \(y = x + 8\).
- This form is great for generating equations quickly when a specific point and slope are known.
- It allows for easy conversion to other forms, like the slope-intercept form, which can be useful for graphing.
The point-slope form is versatile and a handy tool in constructing mathematical representations of linear scenarios.