Chapter 3: Problem 71
Graph each equation. $$ 7 x+3 y=0 $$
Short Answer
Expert verified
The graph is a straight line through (0, 0) and (1, -\(\frac{7}{3}\)).
Step by step solution
01
Identify Form of the Equation
The given equation is \(7x + 3y = 0\). This is a linear equation in the standard form \(Ax + By = C\), where \(A = 7\), \(B = 3\), and \(C = 0\).
02
Find x-intercept
Set \(y = 0\) in the equation to find the x-intercept: \[7x + 3(0) = 0 \]This simplifies to \(7x = 0\), so \(x = 0\). Therefore, the x-intercept is at the point \((0, 0)\).
03
Find y-intercept
Set \(x = 0\) in the equation to find the y-intercept: \[7(0) + 3y = 0\]This simplifies to \(3y = 0\), so \(y = 0\). Therefore, the y-intercept is also at the point \((0, 0)\).
04
Recognize the Line Through the Origin
Since both the x-intercept and y-intercept are at \((0,0)\), this indicates the line passes through the origin (0,0) and has no other distinct intercepts.
05
Plot a Second Point
Select any other value for \(x\) and solve for \(y\) to plot additional points. For example, if \(x = 1\):\[7(1) + 3y = 0 \]Solves to \(3y = -7\), or \(y = -\frac{7}{3}\). Hence, another point on the line is \((1, -\frac{7}{3})\).
06
Draw the Line
Plot the points \((0, 0)\) and \((1, -\frac{7}{3})\) on the graph. Connect these points with a straight line, extending in both directions, to complete the graph of the equation.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Graphing Equations
Graphing linear equations involves plotting points on a coordinate plane so we can visualize the relationship between the variables. In our problem, we have the equation \(7x + 3y = 0\). When graphing a line from an equation like this, we start by identifying key points, such as intercepts, which help us draw the line accurately.
First, we find where the line crosses the x-axis and y-axis. These points are known as the x-intercept and y-intercept. For our specific equation, since both intercepts are the same, it simplifies our task considerably.
First, we find where the line crosses the x-axis and y-axis. These points are known as the x-intercept and y-intercept. For our specific equation, since both intercepts are the same, it simplifies our task considerably.
- Choose any value for \(x\) or \(y\) and compute the other variable.
- Typically, it's best to start with the simplest choices to get intercepts, where one variable is zero.
- Plot these points on a coordinate grid.
X-Intercept
The x-intercept is where a line crosses the x-axis, meaning the value of \(y\) at this point is zero. To find it, we set \(y = 0\) and solve for \(x\). For our equation, \(7x + 3y = 0\), it simplifies to \(7x = 0\) when \(y = 0\).
This results in \(x = 0\), indicating that our x-intercept is at the point \((0, 0)\).
This results in \(x = 0\), indicating that our x-intercept is at the point \((0, 0)\).
- Finding the x-intercept involves basic algebraic manipulation.
- Set any terms with \(y\) equal to zero.
- Solve the resulting equation in terms of \(x\).
Y-Intercept
The y-intercept is where the line meets the y-axis, which means \(x = 0\) at this point, letting us solve for \(y\). With the equation \(7x + 3y = 0\), when \(x = 0\), it becomes \(3y = 0\).
This solves to \(y = 0\), revealing the y-intercept at \((0, 0)\).
This solves to \(y = 0\), revealing the y-intercept at \((0, 0)\).
- The y-intercept is straightforward to find, as it only requires you to replace \(x\) with zero.
- It provides a crucial reference point for drawing the line on a graph.
Standard Form
A linear equation in standard form is written as \(Ax + By = C\). This format showcases the general proportional relationships between \(x\) and \(y\). In our context, \(7x + 3y = 0\), \(A = 7\), \(B = 3\), and \(C = 0\).
Standard form lays out a clean, adaptable framework for any linear equation.
Standard form lays out a clean, adaptable framework for any linear equation.
- \(A\), \(B\), and \(C\) should be integers.
- The form highlights symmetry and intercept values easily.
- It is widely used in teaching for its straightforward presentation of the line.