Chapter 3: Problem 63
Graph each equation. $$ 7 x=4 y-12 $$
Short Answer
Expert verified
The line passes through points (0, 3) and (4, 10) with a slope of \(\frac{7}{4}\).
Step by step solution
01
Rewrite the Equation in Slope-Intercept Form
The slope-intercept form of a line is given by \( y = mx + b \), where \( m \) is the slope and \( b \) is the y-intercept. Start by rewriting the given equation in this form. Given equation: \[ 7x = 4y - 12 \]Add \( 12 \) to both sides: \[ 7x + 12 = 4y \]Divide the entire equation by 4 to solve for \( y \): \[ y = \frac{7}{4}x + 3 \]This shows the slope \( m = \frac{7}{4} \) and the y-intercept \( b = 3 \).
02
Plot the Y-Intercept
Identifying the y-intercept allows you to start graphing the line. The y-intercept is the point where the line crosses the y-axis. From the equation \( y = \frac{7}{4}x + 3 \), the y-intercept \( b = 3 \). Plot the point \((0, 3)\) on the graph.
03
Use the Slope to Find Another Point
Use the slope \( \frac{7}{4} \) to find another point on the line. The slope indicates that for every 4 units you move to the right (increase in \( x \)), the \( y \) value increases by 7 units. Starting from \((0, 3)\), move 4 units to the right to \( x = 4 \), and then move up 7 units to \( y = 10 \). Plot the point \((4, 10)\) on the graph.
04
Draw the Line Through the Points
Now that you have two points on the graph, \((0, 3)\) and \((4, 10)\), draw a straight line through these points. Extend the line in both directions to cover the entire graph.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Slope-Intercept Form
Understanding the slope-intercept form is essential for graphing linear equations. The slope-intercept form is represented by the equation \( y = mx + b \), where:
To convert an equation like \( 7x = 4y - 12 \) into slope-intercept form, we rearrange it so it's in the format of \( y = mx + b \). This involves solving for \( y \), often by performing operations such as addition, subtraction, multiplication, or division.
For example, by adding \( 12 \) to each side and dividing by \( 4 \), we derive \( y = \frac{7}{4}x + 3 \). Now, we can see that the slope \( m \) is \( \frac{7}{4} \), and the y-intercept \( b \) is 3.
This form makes it easier to graph because it directly shows both the slope and the y-intercept, which are critical when plotting on a graph.
- \( m \) represents the slope of the line.
- \( b \) represents the y-intercept, which is where the line crosses the y-axis.
To convert an equation like \( 7x = 4y - 12 \) into slope-intercept form, we rearrange it so it's in the format of \( y = mx + b \). This involves solving for \( y \), often by performing operations such as addition, subtraction, multiplication, or division.
For example, by adding \( 12 \) to each side and dividing by \( 4 \), we derive \( y = \frac{7}{4}x + 3 \). Now, we can see that the slope \( m \) is \( \frac{7}{4} \), and the y-intercept \( b \) is 3.
This form makes it easier to graph because it directly shows both the slope and the y-intercept, which are critical when plotting on a graph.
Y-Intercept
The y-intercept \( b \) plays a crucial role in graphing a linear equation. It tells you the point where the line crosses the y-axis. This point is crucial because it serves as a starting position for graphing the rest of the line.
From the slope-intercept form \( y = \frac{7}{4}x + 3 \), it is evident that \( b = 3 \). This means the line crosses the y-axis at \( (0, 3) \).
To plot the y-intercept on a graph, you simply locate \( 3 \) on the y-axis and put a point there. This is a quick and easy way to begin sketching your graph, as you now have a clear point from which the line will extend.
Remember, plotting the y-intercept does not require any calculations beyond identifying \( b \) in the equation. It's an effortless step yet very important as it guides the direction of the entire line.
From the slope-intercept form \( y = \frac{7}{4}x + 3 \), it is evident that \( b = 3 \). This means the line crosses the y-axis at \( (0, 3) \).
To plot the y-intercept on a graph, you simply locate \( 3 \) on the y-axis and put a point there. This is a quick and easy way to begin sketching your graph, as you now have a clear point from which the line will extend.
Remember, plotting the y-intercept does not require any calculations beyond identifying \( b \) in the equation. It's an effortless step yet very important as it guides the direction of the entire line.
Plotting Points
Once you have the y-intercept plotted, you can use the slope to find additional points on the graph. The slope \( m \) tells you how steep the line is and in which direction it inclines or declines.
The slope \( \frac{7}{4} \) indicates that for every 4 units you move to the right along the x-axis, you move 7 units up on the y-axis. From the y-intercept point \( (0, 3) \), apply the slope by going horizontally to \( x = 4 \) and vertically up to \( y = 10 \). This gives another point on the line, \( (4, 10) \).
When plotting points, it's important to be precise in counting both the rise (change in \( y \)) and the run (change in \( x \)). Accurate plotting ensures your line is correct and represents the equation faithfully.
Once you've plotted the y-intercept and the additional point using the slope, you can draw a line through these points to extend it across the graph. This helps complete the picture of the equation as a line, giving a visual representation of all possible solutions.
The slope \( \frac{7}{4} \) indicates that for every 4 units you move to the right along the x-axis, you move 7 units up on the y-axis. From the y-intercept point \( (0, 3) \), apply the slope by going horizontally to \( x = 4 \) and vertically up to \( y = 10 \). This gives another point on the line, \( (4, 10) \).
When plotting points, it's important to be precise in counting both the rise (change in \( y \)) and the run (change in \( x \)). Accurate plotting ensures your line is correct and represents the equation faithfully.
Once you've plotted the y-intercept and the additional point using the slope, you can draw a line through these points to extend it across the graph. This helps complete the picture of the equation as a line, giving a visual representation of all possible solutions.