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Find an equation of the line that passes through the two given points. Write the equation in slope-intercept form, if possible. See Example 2. Passes through \((-3,0)\) and \((3,1)\)

Short Answer

Expert verified
The equation of the line is \( y = \frac{1}{6}x + \frac{1}{2} \).

Step by step solution

01

Calculate the Slope

To find the equation of a line, we start by calculating the slope \( m \) using the formula: \ \( m = \frac{y_2 - y_1}{x_2 - x_1} \) \ Plugging in the points \((-3,0)\) and \((3,1)\), we have \ \( m = \frac{1 - 0}{3 - (-3)} = \frac{1}{6} \)
02

Use Point-Slope Form to Write the Equation

Using the point-slope form \( y - y_1 = m(x - x_1) \), we can substitute the slope \( m = \frac{1}{6} \) and one of the points, \((-3, 0)\), into the equation. \ \( y - 0 = \frac{1}{6}(x + 3) \) \ Which simplifies to \( y = \frac{1}{6}x + \frac{1}{2} \).
03

Write the Equation in Slope-Intercept Form

The slope-intercept form is \( y = mx + b \) where \( m \) is the slope and \( b \) is the y-intercept. In the previous step, we already have it in slope-intercept form: \ \( y = \frac{1}{6}x + \frac{1}{2} \).
04

Verify with the Second Point

To ensure the equation is correct, substitute the second point \((3, 1)\) into the equation \( y = \frac{1}{6}x + \frac{1}{2} \) and verify: \ Substitute \(3\) for \(x\): \ \( y = \frac{1}{6}(3) + \frac{1}{2} = \frac{1}{2} + \frac{1}{2} = 1 \). \ Since both points satisfy the equation, it is correct.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope Calculation
Calculating the slope is the first step in finding the equation of a line given two points. The slope is essential because it shows how steep a line is, or how much the y-value changes when the x-value changes. It is often represented by the letter "m". The formula to find the slope between two points \(x_1, y_1\) and \(x_2, y_2\) is:
\[ m = \frac{y_2 - y_1}{x_2 - x_1} \]
This formula calculates the "rise" (change in y) over the "run" (change in x).
For example, if you have the points \((-3,0)\) and \(3,1)\), you substitute these into the formula like this:
\[ m = \frac{1 - 0}{3 - (-3)} = \frac{1}{6} \].
Here, the slope \(m\) turns out to be \(\frac{1}{6}\), indicating a gentle upward incline. This information tells you that for each step you take to the right along the x-axis, the line rises \(\frac{1}{6}\) of a unit.
Point-Slope Form
The point-slope form of the equation of a line is handy when you know the slope and at least one point through which the line passes. This form is written as:
\[ y - y_1 = m(x - x_1) \]
where \(m\) is the slope, and \(x_1, y_1\) is a specific point on the line.
Using the point-slope form makes it relatively easy to find an equation of a line when given two points.
For our example with the calculated slope \(\frac{1}{6}\) and the point \((-3, 0)\), you plug these values into the formula:
\[ y - 0 = \frac{1}{6}(x + 3) \],
which simplifies to
\[ y = \frac{1}{6}x + \frac{1}{2} \].
This form of the equation clearly shows the line's slope and confirms one point through which the line passes.
Linear Equations
Understanding linear equations is fundamental in algebra. A linear equation in two variables represents a straight line graphically. The most common form of a linear equation is the slope-intercept form, expressed as \( y = mx + b \)
Here, \( m \) represents the slope, while \( b \) is the y-intercept; the point where the line crosses the y-axis.

In our exercise, upon using the point-slope form and simplifying, we arrived at the slope-intercept form:
\[ y = \frac{1}{6}x + \frac{1}{2} \].
This tells us the line crosses the y-axis at \(\frac{1}{2}\) and confirms the slope is \(\frac{1}{6}\).
Linear equations are powerful because knowing two basic things — the slope and the y-intercept — allows you to graph the line and understand its behavior entirely, including predicting further points on the line.

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