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91Ó°ÊÓ

Determine whether the relation defines to be a function of . If a function is defined, give its domain and range. If it does not define a function, find two ordered pairs that show a value of that is assigned more than one value of . See Example 2. $$ \begin{array}{|l|r|} \hline x & {y} \\ \hline 3 & {4} \\ {3} & {-4} \\ {4} & {3} \\ {4} & {-3} \\ \hline \end{array} $$

Short Answer

Expert verified
The relation does not define a function of \( x \) because \( x = 3 \) and \( x = 4 \) each correspond to two different \( y \)-values.

Step by step solution

01

Understanding Functions

A relation defines a function if every value of \( x \) is associated with one and only one value of \( y \). In other words, for every \( x \)-value in the domain, there should be a unique \( y \)-value.
02

Examine the Ordered Pairs

The given relation includes the pairs \((3, 4)\), \((3, -4)\), \((4, 3)\), and \((4, -3)\). Examine each \( x \)-value to check how many unique \( y \)-values it corresponds to.
03

Analyze \( x = 3 \)

The \( x \)-value 3 is associated with the \( y \)-values 4 and -4. This means for \( x = 3 \), there are two different \( y \)-values, violating the definition of a function.
04

Analyze \( x = 4 \)

Similarly, the \( x \)-value 4 is associated with the \( y \)-values 3 and -3. Similar to the previous case, this \( x \)-value also corresponds to two different \( y \)-values.
05

Conclusion

Since for \( x = 3 \) and \( x = 4 \), there are multiple \( y \)-values, the relation does not define \( y \) as a function of \( x \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Domain and Range
In mathematics, every function has two important parts: the domain and the range.
The domain of a function is the complete set of possible values of the independent variable, usually represented by the letter \( x \). This means, basically, all the \( x \)-values you can plug into the function to get a \( y \)-value back. Conversely, the range is the set of all possible \( y \)-values which we will get after plugging in the \( x \)-values into the function.

For a relation to be considered a function, each \( x \)-value in the domain must relate to exactly one \( y \)-value in the range.
  • If any \( x \)-value is paired with more than one \( y \)-value, then we do not have a function.
In our original problem, the presence of multiple \( y \)-values for a given \( x \), such as both 4 and -4 for \( x = 3 \), prevents the relation from being a function.
Ordered Pairs
Ordered pairs are a fundamental concept when dealing with relations and functions.
They're simply pairs of numbers, usually written in the form \((x, y)\), with \( x \) representing a point on the horizontal axis, and \( y \) representing a point on the vertical axis.

These pairs describe a specific relationship between \( x \) and \( y \), and are used to map the connection between inputs and outputs. Each pair tells you that for a certain input \( x \), we receive a specific output \( y \).
  • In the context of our problem, we look at ordered pairs such as \((3, 4)\) and \((3, -4)\) to determine if the relation constitutes a function.
If any \( x \)-value appears more than once with different \( y \)-values, like \( (3, 4) \) and \( (3, -4) \), the relation does not satisfy the criteria of defining a function.
Function Definition
To understand functions, we must first grasp the precise definition.
A function in mathematics is defined as a special relation between sets. Here, every element in the first set (the domain) is associated with exactly one element in the second set (the range).

This means each \( x \)-value should connect to a single \( y \)-value, ensuring clarity in mapping inputs to outputs without ambiguity.
  • In our example exercise, multiple \( y \)-values (e.g., 4 and -4) linked to the same \( x \)-values (e.g., \( x = 3 \)) breach this rule.
These violations in what the function definition stipulates demonstrate why such a relation doesn't constitute a proper function. Understanding this pivotal concept helps avoid confusion when examining relations.

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