Chapter 2: Problem 44
Liquid mixture problems. One website recommends a \(6 \%\) chlorine bleach-water solution to remove mildew. A chemical lab has \(3 \%\) and \(15 \%\) chlorine bleach-water solutions in stock. How many gallons of each should be mixed to obtain 100 gallons of the mildew spray?
Short Answer
Expert verified
75 gallons of 3% solution and 25 gallons of 15% solution are needed.
Step by step solution
01
Understand the Problem
We need to combine two different chlorine solutions to make a total of 100 gallons of a 6% chlorine solution. We have a 3% solution and a 15% solution available.
02
Define Variables
Let \( x \) represent the number of gallons of the 3% solution, and \( y \) represent the number of gallons of the 15% solution. We know that \( x + y = 100 \).
03
Set Up the Chlorine Equation
The total amount of chlorine in the mixture is determined by the amount from each solution. The chlorine from the 3% solution is \( 0.03x \) and from the 15% solution is \( 0.15y \). The total chlorine should equal 6% of the final 100 gallons: \( 0.06 \times 100 = 6 \).
04
Write the System of Equations
We have two equations: 1. \( x + y = 100 \)2. \( 0.03x + 0.15y = 6 \)
05
Solve the System of Equations
Substitute \( y = 100 - x \) into the second equation:\( 0.03x + 0.15(100 - x) = 6 \). Simplify this to get \( 0.15 \times 100 - 0.15x + 0.03x = 6 \) which simplifies to \( 15 - 0.12x = 6 \). Solve for \( x \) to get \( 0.12x = 9 \), so \( x = 75 \). Then \( y = 100 - 75 = 25 \).
06
Verify the Solution
Substitute \( x = 75 \) and \( y = 25 \) back into the chlorine equation: \( 0.03 \times 75 + 0.15 \times 25 = 2.25 + 3.75 = 6 \). Since the chlorine equation holds, the amounts are correct.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Systems of Equations
Mixture problems often involve finding amounts of ingredients to form a desired final product. To achieve this, we can use systems of equations as a mathematical tool. In a system of equations, you have two or more equations working together. The goal is to find values for the variables that make all the equations true simultaneously.
### Why Use Systems of Equations?
### Why Use Systems of Equations?
- **Balance**: They help keep quantities in balance by taking multiple relationships into account at once.
- **Precision**: They ensure accurate and consistent solutions.
Percentages
Working with percentages is crucial in mixture problems, especially for determining concentrations and proportions. A percentage represents a part of a whole and it is used to express how much of a certain component is present compared to the total quantity.
### How Percentages Work
### How Percentages Work
- **Representation**: A percentage like 3% or 15% is a way to express parts per hundred. It tells you how many parts of something are in each 100 parts of the whole mixture.
- **Conversion**: To work with percentages in equations, convert them to decimals by dividing by 100. For example, 3% becomes 0.03 and 15% becomes 0.15.
Solution Concentration
Solution concentration refers to how much solute is dissolved in a solvent. In a mixture problem, it's concerned with determining how strong or dilute a solution is by the proportions of solute and solvent.
### Calculating Concentration
### Calculating Concentration
- **Solution Terms**: The solution here is a bleach-water mixture, where chlorine is the common solute.
- **Concentration Determination**: The concentration of 6% means that out of 100 gallons, 6 gallons must be pure chlorine.