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Solve each equation and check the result. $$ \frac{1}{8} y-\frac{1}{2}=\frac{1}{4} $$

Short Answer

Expert verified
The solution is \( y = 6 \).

Step by step solution

01

Isolate the Variable Term

To solve for \( y \), first eliminate the constant term on the left side of the equation. The equation given is: \[ \frac{1}{8}y - \frac{1}{2} = \frac{1}{4} \] Add \( \frac{1}{2} \) to both sides to isolate the term containing \( y \): \[ \frac{1}{8}y = \frac{1}{4} + \frac{1}{2} \]
02

Add the Fractions

Next, find a common denominator to add the fractions on the right side of the equation. The common denominator for \( \frac{1}{4} \) and \( \frac{1}{2} \) is 4. Convert \( \frac{1}{2} \) to have this common denominator: \[ \frac{1}{2} = \frac{2}{4} \] Now add the fractions: \[ \frac{1}{4} + \frac{2}{4} = \frac{3}{4} \] The equation is now: \[ \frac{1}{8}y = \frac{3}{4} \]
03

Solve for \( y \)

To solve for \( y \), multiply both sides of the equation by 8 (to cancel out the \( \frac{1}{8} \) multiple of \( y \)): \[ y = 8 \times \frac{3}{4} \] Simplify the right side by performing the multiplication: \[ y = \frac{24}{4} \] Reduce \( \frac{24}{4} \) to get: \[ y = 6 \]
04

Check the Solution

Substitute \( y = 6 \) back into the original equation to verify the solution is correct: \[ \frac{1}{8}y - \frac{1}{2} = \frac{1}{4} \] Substitute \( y = 6 \): \[ \frac{1}{8}(6) - \frac{1}{2} = \frac{1}{4} \] Calculate \( \frac{1}{8}(6) = \frac{6}{8} = \frac{3}{4} \).Then, \( \frac{3}{4} - \frac{1}{2} = \frac{3}{4} - \frac{2}{4} = \frac{1}{4} \).Both sides equal \( \frac{1}{4} \), confirming the solution checks out.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Fractions
Fractions represent parts of a whole and are composed of a numerator (top part) and a denominator (bottom part). Understanding how fractions work is essential, especially when you're dealing with algebraic equations involving fractions. For example, in the equation \( \frac{1}{8}y - \frac{1}{2} = \frac{1}{4} \), each number is a fraction:
  • The numerator tells you how many parts you have.
  • The denominator tells you how many parts make up a whole.
When you're adding or subtracting fractions, you need a common denominator. The denominator represents the total number of equal parts a whole is divided into, and it must be the same when performing these operations. This is why when you add \( \frac{1}{4} \) and \( \frac{1}{2} \), you need to convert \( \frac{1}{2} \) to \( \frac{2}{4} \) to have a common denominator. Once fractions share the same denominator, you add or subtract just the numerators. Remember these key points:
  • Find a common denominator to add or subtract.
  • Convert fractions as necessary to match the common denominator.
  • Perform operations on numerators, keeping the denominator unchanged.
Solving for Variables
Solving for a variable means isolating that variable on one side of the equation. This process involves several key steps:
  • First, move any constant terms to the opposite side of the equation. For instance, in the problem \( \frac{1}{8}y - \frac{1}{2} = \frac{1}{4} \), you add \( \frac{1}{2} \) to both sides to isolate the term with \( y \).
  • Next, you deal directly with the fractions involved. We added \( \frac{1}{2} \) to \( \frac{1}{4} \) by finding a common denominator, which in this case is 4.
  • Once you have the fractions sorted out, simplify them. The equation \( \frac{1}{8}y = \frac{3}{4} \) follows after adding the fractions.
  • Finally, perform the operations needed to solve for the variable. Since \( y \) was multiplied by \( \frac{1}{8} \), you multiply both sides of the equation by 8 to solve for \( y \).
Ultimately, your goal is to have the variable by itself on one side of the equation. In this exercise, we ended up with \( y = 6 \). Remember:
  • Identify operations inversely affecting the variable.
  • Perform operations to inverse these effects stepwise manner.
  • Aim to simplify the equation with each step.
Checking Solutions
Once you've solved for a variable, it's crucial to confirm that your solution is correct. This involves substituting the found value back into the original equation. Here's how:
  • Take the solution you've calculated, in this case, \( y = 6 \).
  • Replace the variable (\( y \)) in the original equation with this value.
  • Re-evaluate the equation to ensure both sides are equal.
In the equation \( \frac{1}{8}y - \frac{1}{2} = \frac{1}{4} \), substituting \( y = 6 \) gives \( \frac{1}{8}(6) - \frac{1}{2} = \frac{1}{4} \). Simplify this step by step:- Calculate \( \frac{1}{8} \times 6 = \frac{6}{8} = \frac{3}{4} \).- Subtract \( \frac{1}{2} \) from \( \frac{3}{4} \), converting if necessary, to get \( \frac{1}{4} \).This confirms that both sides are equal, verifying the result is correct. When checking solutions:
  • Always substitute back into the original equation.
  • Perform all operations carefully to verify equality.
  • Consider repeating if the result doesn't initially check out, as this may indicate a mistake in calculations.

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