Chapter 14: Problem 60
Use the binomial theorem to expand each expression. See Examples 5 and 6. $$ (c+d)^{5} $$
Short Answer
Expert verified
The expansion of \((c + d)^5\) is \(c^5 + 5c^4d + 10c^3d^2 + 10c^2d^3 + 5cd^4 + d^5\).
Step by step solution
01
Understanding the Binomial Theorem
The binomial theorem expresses a binomial raised to a power as the sum of terms involving binomial coefficients. The binomial theorem states that: \((a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k\), where \(\binom{n}{k}\) are the binomial coefficients.
02
Identify the Parameters
In the expression \((c+d)^5\), identify the parameters: \(a = c\), \(b = d\), and \(n = 5\).
03
Calculate Binomial Coefficients
For \(n = 5\), we calculate the binomial coefficients \(\binom{5}{k}\) for \(k\) from 0 to 5:- \(\binom{5}{0} = 1\),- \(\binom{5}{1} = 5\),- \(\binom{5}{2} = 10\),- \(\binom{5}{3} = 10\),- \(\binom{5}{4} = 5\),- \(\binom{5}{5} = 1\).
04
Write Terms Using Theorem
Using the binomial theorem and the coefficients calculated:- For \(k = 0\): \(\binom{5}{0} c^{5-0} d^0 = c^5\),- For \(k = 1\): \(\binom{5}{1} c^{5-1} d^1 = 5c^4d\),- For \(k = 2\): \(\binom{5}{2} c^{5-2} d^2 = 10c^3d^2\),- For \(k = 3\): \(\binom{5}{3} c^{5-3} d^3 = 10c^2d^3\),- For \(k = 4\): \(\binom{5}{4} c^{5-4} d^4 = 5cd^4\),- For \(k = 5\): \(\binom{5}{5} c^{5-5} d^5 = d^5\).
05
Combine the Terms
Adding all the terms together, the expansion of \((c + d)^5\) is:\[c^5 + 5c^4d + 10c^3d^2 + 10c^2d^3 + 5cd^4 + d^5.\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Binomial Coefficients
The binomial coefficients play a central role in the expansion of expressions using the binomial theorem. These coefficients are represented by \( \binom{n}{k} \), which is read as "n choose k". It signifies the number of ways to choose \( k \) elements from a set of \( n \) elements without regard to order.
Calculating binomial coefficients involves using the formula \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \), where "!" denotes factorial, the product of all positive integers up to that number.
In our example, the expression \((c+d)^5\) involves several binomial coefficients:
Calculating binomial coefficients involves using the formula \( \binom{n}{k} = \frac{n!}{k!(n-k)!} \), where "!" denotes factorial, the product of all positive integers up to that number.
In our example, the expression \((c+d)^5\) involves several binomial coefficients:
- \(\binom{5}{0} = 1\): This indicates there is only one way to choose none of the elements, simply resulting in \(1\).
- \(\binom{5}{1} = 5\): There are 5 ways to choose one element from five, hence 5 arrangements.
- \(\binom{5}{2} = 10\): This shows there are 10 ways to choose 2 elements from 5.
Polynomial Expansion
Expanding a binomial expression involves expressing it as a polynomial. This means writing the expression in a form like \(a_0x^{n} + a_1x^{n-1}y + \dots + a_ny^{n}\).
Using the binomial theorem, you can transform any expression of the form \((a + b)^n\) into a series of terms. Each term is a combination of the binomial coefficients, the base elements \(a\) and \(b\), and their powers.
For the expression \((c+d)^5\), the polynomial expansion is:
Using the binomial theorem, you can transform any expression of the form \((a + b)^n\) into a series of terms. Each term is a combination of the binomial coefficients, the base elements \(a\) and \(b\), and their powers.
For the expression \((c+d)^5\), the polynomial expansion is:
- First term: \(c^5\) (when all powers are with \(c\))
- Second term: \(5c^4d\)
- Third term: \(10c^3d^2\)
- Fourth term: \(10c^2d^3\)
- Fifth term: \(5cd^4\)
- Sixth term: \(d^5\) (when all powers are with \(d\))
Algebraic Expressions
Algebraic expressions are the foundation of algebra, representing mathematical phrases involving numbers, variables, and operations. A key part of understanding expressions like \((c+d)^5\) involves recognizing how each variable and constant interact with one another.
In the expression \((c+d)^5\), \(c\) and \(d\) are variables that can represent any numbers. The exponent 5 tells us that \(c + d\) is multiplied by itself 5 times. With binomial expansion, this repeated multiplication process is simplified.
Algebraic expressions obey several important properties which allow them to be transformed and simplified:
In the expression \((c+d)^5\), \(c\) and \(d\) are variables that can represent any numbers. The exponent 5 tells us that \(c + d\) is multiplied by itself 5 times. With binomial expansion, this repeated multiplication process is simplified.
Algebraic expressions obey several important properties which allow them to be transformed and simplified:
- Commutative Property: For addition, \(a + b = b + a\). This helps in rearranging terms for simplicity.
- Associative Property: This property allows grouping, such as \((a + b) + c = a + (b + c)\).
- Distributive Property: Multiplying a sum by a number gives the same result as doing each multiplication separately, e.g., \(a(b+c) = ab + ac\).