Chapter 12: Problem 42
A pet store owner spent \(\$ 100\) to buy 100 animals. He bought at least one iguana, one guinea pig, and one mouse, but no other kinds of animals. If an iguana cost \(\$ 10.00,\) a guinea pig cost \(\$ 3.00,\) and a mouse cost \(\$ 0.50,\) how many of each did he buy?
Short Answer
Expert verified
5 iguanas, 1 guinea pig, 94 mice.
Step by step solution
01
Analyze the Variables and Constraints
Let the number of iguanas be \( x \), guinea pigs be \( y \), and mice be \( z \). We know there are 100 animals in total, so \( x + y + z = 100 \). The total cost is \$100, hence \( 10x + 3y + 0.5z = 100 \). There must be at least one of each animal, so \( x \geq 1 \), \( y \geq 1 \), and \( z \geq 1 \).
02
Substitute Variables and Simplify
From \( x + y + z = 100 \), express \( z \) in terms of \( x \) and \( y \): \( z = 100 - x - y \). Substitute this into the cost equation: \( 10x + 3y + 0.5(100 - x - y) = 100 \). Simplifying gives: \( 10x + 3y + 50 - 0.5x - 0.5y = 100 \). Further simplification yields \( 9.5x + 2.5y = 50 \).
03
Simplify and Solve the System of Equations
We now have \( 9.5x + 2.5y = 50 \). Multiply all terms by 2 to eliminate decimals: \( 19x + 5y = 100 \). This equation, along with \( x + y + z = 100 \), helps us find integer values for \( x \), \( y \), and \( z \).
04
Guess and Check for Integer Solutions
Using some logical guessing, since iguanas and guinea pigs are pricier, start checking with smaller values of \( z \). Assume \( x = 5 \) and \( y = 1 \) (start small to check): \( 19(5) + 5(1) = 95 + 5 = 100 \). Thus, \( x = 5 \, \text{iguana}, \ y = 1 \, \text{guinea pig}, \ z = 94 \, \text{mouse}.\) Substituting verifies: \( 5 \times 10 + 1 \times 3 + 94 \times 0.5 = 50 + 3 + 47 = 100 \).
05
Confirm the Solution
Check total number of animals: \( x + y + z = 5 + 1 + 94 = 100 \). Cost check: \( 5 \times 10 + 1 \times 3 + 94 \times 0.5 = 100 \). Hence, the solution \( x = 5 \) iguanas, \( y = 1 \) guinea pig, and \( z = 94 \) mice satisfies all conditions.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Systems of Equations
Solving problems involving systems of equations is a skill that expands our understanding of relationships between different variables. In the given pet store problem, we have two essential equations:
- The first equation, \( x + y + z = 100 \), represents the total number of animals.
- The second equation, \( 10x + 3y + 0.5z = 100 \), reflects the total cost spent on these animals.
Problem Solving Strategies
Approaching word problems effectively often involves breaking down the task into smaller, manageable parts, much like solving a puzzle step by step.
- Firstly, we identify and define the variables, here being the types of animals: iguanas, guinea pigs, and mice.
- Secondly, explore the relationship between variables through equations derived from the problem statement.
- Thirdly, strategically solve the systems using substitution or elimination to simplify and reduce variables.
Integer Solutions
Many real-world problems, like this algebra word problem, require solutions in integers, meaning whole numbers, because you cannot have a fraction of a live animal.
- Each variable, representing a type of pet, must be an integer, as you can't purchase half an animal.
- To achieve integer solutions, we may need to manipulate or transform equations, such as multiplying through by a factor to clear decimals (e.g., multiplying by 2 to transform \( 9.5x + 2.5y = 50 \) into \( 19x + 5y = 100 \)).
- Integer constraints add an additional layer of logical reasoning and often involve hypothesis testing to find solutions that fit all constraints seamlessly.