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Solve each system. If a system is inconsistent or if the equations are dependent, state this. $$ \left\\{\begin{array}{l} 2 a-b+c=6 \\ -5 a-2 b-4 c=-30 \\ a+b+c=8 \end{array}\right. $$

Short Answer

Expert verified
The system has infinitely many solutions; it's dependent.

Step by step solution

01

Analyze the system of equations

We are given three equations with three variables: \(2a - b + c = 6\), \(-5a - 2b - 4c = -30\), \(a + b + c = 8\). We need to solve for \(a\), \(b\), and \(c\).
02

Eliminate a variable from two equations

Let's eliminate \(c\) by manipulating the first and third equations. From Eq. 1: \(c = 6 + b - 2a\). Substitute into Eq. 3: \(a + b + (6 + b - 2a) = 8\). Simplifying, \(-a + 2b + 6 = 8\), giving \(-a + 2b = 2\). This is our new Eq. 4.
03

Substitute and simplify the second equation

Now substitute Eq. 1's expression for \(c\) into Eq. 2: \(-5a - 2b - 4(6 + b - 2a) = -30\). Simplifying, \(-5a - 2b - 24 - 4b + 8a = -30\), which rearranges to \(3a - 6b = -6\). This is our Eq. 5 after dividing by 3: \(a - 2b = -2\).
04

Solve the new system of equations

We have two equations now: \(-a + 2b = 2\) (Eq. 4) and \(a - 2b = -2\) (Eq. 5). Adding these two equations cancels out both \(a\) and \(b\) terms, resulting in \(0 = 0\), which indicates a dependent system. Therefore, the original system has infinitely many solutions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Dependent Systems
In the world of algebra, a dependent system refers to a situation where the equations in a system are not distinct from each other. This means they essentially describe the same geometric object or line, rather than multiple ones intersecting. For example, in a two-variable scenario, this would translate to two lines that overlap completely, meaning they have every point in common.

In our exercise, the equations ultimately led to a statement like "0 = 0," which is always true. This indicates that no new information was gleaned from one equation over another. Hence, the entire system is dependent.

Understanding dependent systems is crucial as it helps us avoid unnecessary calculations. Instead of looking for a single solution, we aim to understand the conditions under which infinitely many solutions can exist.
Infinitely Many Solutions
A system with infinitely many solutions occurs when the equations in the system describe the same geometric entity in space, such as a line in two dimensions or a plane in three dimensions. This reflects the idea that there is not just one unique solution, but rather a whole set of solutions that satisfies all equations simultaneously.

In our system of equations:
  • Equation 1: \(2a - b + c = 6\)
  • Equation 2: \(-5a - 2b - 4c = -30\)
  • Equation 3: \(a + b + c = 8\)
the dependent nature means that any combination of \(a\), \(b\), and \(c\) that satisfies one equation also satisfies the others. During the solution process, we ended up with a statement of equality \(0 = 0\), which affirmed that the equations were not providing new, unique constraints.

This is key in understanding that each solution is not just an arbitrary point, but part of a larger family of solutions sharing a common trait.
Variable Elimination
The technique of variable elimination is a strategic way to simplify solving a system of equations by reducing the number of unknowns systematically. This involves adjusting the equations strategically to cancel out one variable at a time, allowing you to focus on solving for the remaining variables.

In the provided exercise, we started by eliminating variable \(c\) from the first and third equations by expressing \(c\) in terms of \(a\) and \(b\). Then, this expression was substituted into other equations to reduce the system to fewer variables. This process simplifies the system to one that is more manageable and leads us to equations that more clearly reveal the relationship between the variables.

Key steps in variable elimination involve:
  • Isolating one variable in one equation.
  • Substituting it into the other equations.
  • Simplifying and solving the resulting equations.
This technique is foundational in algebra, providing a stepping stone towards finding solutions or understanding when a system does not have a unique solution, as was the case in our dependent system with infinitely many solutions.

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Most popular questions from this chapter

Solve each system by elimination (addition). $$ \left\\{\begin{array}{l} \frac{5}{6} x+\frac{1}{2} y=12 \\ 0.3 x+0.5 y=5.6 \end{array}\right. $$

Write a system of two equations in two variables to solve each problem. cosmotology. A beauty shop specializing in permanents has fixed costs of \(\$ 2,101.20\) per month. The owner estimates that the cost for each permanent is \(\$ 23.60\), which covers labor, chemicals, and electricity. If her shop can give as many permanents as she wants at a price of \(\$ 44\) each, how many must be given each month for her to break even?

Write a system of two equations in two variables to solve each problem. Farming. \(\quad\) A farmer keeps some animals on a strict diet. Each animal is to receive 15 grams of protein and 7.5 grams of carbohydrates. The farmer uses two food mixes, with nutrients as shown in the table. How many grams of each mix should be used to provide the correct nutrients for each animal? $$ \begin{array}{|l|c|c|} \hline \text { Mix } & \text { Protein } & \text { Carbohydrates } \\ \hline \operatorname{Mix} \mathrm{A} & 12 \% & 9 \% \\ \operatorname{Mix} \mathrm{B} & 15 \% & 5 \% \\ \hline \end{array} $$

Use Cramer's rule to solve system of equations. If a system is inconsistent or if the equations are dependent, so indicate. \(\left\\{\begin{array}{l}4 x+3 z=4 \\ 2 y-6 z=-1 \\ 8 x+4 y+3 z=9\end{array}\right.\)

Solve each system by graphing, if possible. If a system is inconsistent or if the equations are dependent, state this. (Hint: Several coordinates of points of intersection are fractions.) $$ \left\\{\begin{array}{l} y=-2 \\ y=\frac{2}{3} x-\frac{4}{3} \end{array}\right. $$

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