Chapter 12: Problem 29
Use matrices to solve each system of equations. \(\left\\{\begin{array}{l}x+y+z=6 \\ x+2 y+z=8 \\ x+y+2 z=7\end{array}\right.\)
Short Answer
Expert verified
The solution to the system is \(x = 3\), \(y = 1\), \(z = 2\).
Step by step solution
01
Write the System in Matrix Form
First, express the system of equations in matrix form, which is \[ AX = B \]where \[ A = \begin{bmatrix} 1 & 1 & 1 \ 1 & 2 & 1 \ 1 & 1 & 2 \end{bmatrix}, \quad X = \begin{bmatrix} x \ y \ z \end{bmatrix}, \quad B = \begin{bmatrix} 6 \ 8 \ 7 \end{bmatrix} \]
02
Calculate the Inverse of Matrix A
To solve for \(X\), we need to find the inverse of matrix \(A\). The inverse \(A^{-1}\) can be calculated using the formula for the inverse of a 3x3 matrix. Compute determinant \(|A| = 1(2*2 - 1*1) - 1(1*2 - 1*1) + 1(1*1 - 1*2) = 1.\) Thus, the determinant is non-zero, and the inverse exists.
03
Derive the Inverse Matrix
Now, using \\[ A^{-1} = \frac{1}{|A|} \text{adj}(A) \]compute the adjugate of \(A\): \[\text{adj}(A) = \begin{bmatrix} 3 & -1 & -1 \ -1 & 1 & 0 \ -1 & 0 & 1 \end{bmatrix}.\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
System of Equations
Understanding a system of equations is crucial in mathematical applications, especially when we deal with multiple variables.
In simple terms, a system of equations is a collection of two or more equations with a common set of unknowns.
This means you're trying to find the values of the variables that satisfy all the equations in the system simultaneously.When approaching a system of equations, it’s often presented in the form:
Matrices can be a powerful tool in analyzing and solving these systems, as they offer a structured and compact form.
This leads us to our next concept: matrices and their inverses.
In simple terms, a system of equations is a collection of two or more equations with a common set of unknowns.
This means you're trying to find the values of the variables that satisfy all the equations in the system simultaneously.When approaching a system of equations, it’s often presented in the form:
- Linear equations, where each equation is a straight line (in two or three dimensions)
- Non-linear equations, which might include curves, parabolas, etc.
Matrices can be a powerful tool in analyzing and solving these systems, as they offer a structured and compact form.
This leads us to our next concept: matrices and their inverses.
Inverse of a Matrix
Not all matrices have inverses, but when they do, it can significantly simplify solving systems of equations.
The inverse of a matrix \(A\), denoted as \(A^{-1}\), is akin to the reciprocal of a number, where multiplying a matrix by its inverse results in the identity matrix.
If the determinant is non-zero, you can then find the adjugate matrix and use it to compute \(A^{-1}\).In our exercise, the matrix \(A\) was:\[A = \begin{bmatrix} 1 & 1 & 1 \ 1 & 2 & 1 \ 1 & 1 & 2 \end{bmatrix}\]Computing its inverse involves determining its determinant and construct its adjugate to form \(A^{-1}\).
This step allows us to proceed correctly to find solutions for our set of equations.
The inverse of a matrix \(A\), denoted as \(A^{-1}\), is akin to the reciprocal of a number, where multiplying a matrix by its inverse results in the identity matrix.
- If \(A\) is a square matrix (same number of rows and columns), we can find its inverse, provided its determinant is non-zero.
- The identity matrix \(I\) is the equivalent of the number 1 in matrix algebra, as \(A \times A^{-1} = I\).
If the determinant is non-zero, you can then find the adjugate matrix and use it to compute \(A^{-1}\).In our exercise, the matrix \(A\) was:\[A = \begin{bmatrix} 1 & 1 & 1 \ 1 & 2 & 1 \ 1 & 1 & 2 \end{bmatrix}\]Computing its inverse involves determining its determinant and construct its adjugate to form \(A^{-1}\).
This step allows us to proceed correctly to find solutions for our set of equations.
Determinant of a Matrix
The determinant of a matrix is a special number defined only for square matrices and is essential in matrix algebra.
A non-zero determinant indicates that the matrix is invertible, while a zero determinant means no inverse exists.Understanding determinants can help determine if a particular system of equations has a unique solution.
For a 3x3 matrix, the determinant can be computed using the formula:\[|A| = a(ei − fh) − b(di − fg) + c(dh − eg)\]Where \(a, b, c, d, e, f, g, h, i\) are elements of the matrix arranged in the following manner:\[\begin{bmatrix} a & b & c \ d & e & f \ g & h & i \end{bmatrix}\]In our problem, the matrix \(A\) has a determinant:\[|A| = 1(2 \times 2 - 1 \times 1) - 1(1 \times 2 - 1 \times 1) + 1(1 \times 1 - 1 \times 2) = 1\]This non-zero result confirms that the inverse exists, enabling further steps in solving the equations.Determinants serve as a foundational concept not only in solving equations but also in understanding linear transformations and other more complex mathematical concepts.
A non-zero determinant indicates that the matrix is invertible, while a zero determinant means no inverse exists.Understanding determinants can help determine if a particular system of equations has a unique solution.
For a 3x3 matrix, the determinant can be computed using the formula:\[|A| = a(ei − fh) − b(di − fg) + c(dh − eg)\]Where \(a, b, c, d, e, f, g, h, i\) are elements of the matrix arranged in the following manner:\[\begin{bmatrix} a & b & c \ d & e & f \ g & h & i \end{bmatrix}\]In our problem, the matrix \(A\) has a determinant:\[|A| = 1(2 \times 2 - 1 \times 1) - 1(1 \times 2 - 1 \times 1) + 1(1 \times 1 - 1 \times 2) = 1\]This non-zero result confirms that the inverse exists, enabling further steps in solving the equations.Determinants serve as a foundational concept not only in solving equations but also in understanding linear transformations and other more complex mathematical concepts.